Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 21 Jan 2017, 02:54

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

Author Message
SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

19 Jun 2003, 00:15
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

|C–|2C|C|||=C

Manager
Joined: 03 Jun 2003
Posts: 84
Location: Uruguay
Followers: 1

Kudos [?]: 0 [0], given: 0

### Show Tags

19 Jun 2003, 11:48
I hope you don┬┤t get angry this time (if I fail)

SVP
Joined: 03 Feb 2003
Posts: 1603
Followers: 8

Kudos [?]: 245 [0], given: 0

### Show Tags

19 Jun 2003, 21:32
My solution:

|C–|2C|C|||=C ---- thus C>=0, remember that

CASE # 1 the undermodul stuff is nonnegative
C–|2C|C||=C
|2C|C||=0
C=0 seems OK

CASE# 2 the undermodul stuff is negative
C–|2C|C||=–C
|2C|C||=2C square both parts
4C^2*C^2=4C^2
C=0, C=1, C=–1, which does not match to the initial condition

Therefore: C={0, 1}
19 Jun 2003, 21:32
Display posts from previous: Sort by

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.