Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:
How can we do this quickly? [#permalink]
25 Aug 2004, 17:32
This topic is locked. If you want to discuss this question please re-post it in the respective forum.
For years, everyone's been talking about plugging in numbers for algebra problems. You pick a number for the variable, plug it in, get an answer, and then find that answer in the answer choices.
I think this is dangerous, because it only works sometimes, and I think that algebra or some other trick is always important as a backup. Plugging in should be done by people who understand it and when not to use it.
Sorry for waxing on about that, but I ran across a problem today that would be very difficult to plug numbers into, but is also very time consuming using straightforward algebra. You might expect it to work out well with substitution, but you'll see that it doesn't. So I thought I'd post it here and see what everyone thought about it, and if there's some clever thing that I'm not seeing.
If 2x + 3y = 1, what is (x/2) + (y/3) in terms of y?
B) (1 - 3y)/2
C) (1 - 3y)/4
D) (3y + 4)/15
E) (3 - 5y)/12
Last edited by ian7777 on 25 Aug 2004, 17:56, edited 1 time in total.
(E). 20 secs. I think good old substitution is still very fast in this case. If you note that you'll end up with 2 and 3 as denominator, you can work two steps ahead while substituting by adjusting the integer value of y as you work throuhg the problem.