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How long did it take Carlos to drive nonstop from his home

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How long did it take Carlos to drive nonstop from his home [#permalink] New post 15 Mar 2012, 14:13
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Question Stats:

63% (01:40) correct 36% (00:49) wrong based on 3 sessions
How long did it take Carlos to drive nonstop from his home to Atlanta, Georgia?

(1) Carlos’s average speed for the trip was 55 miles per hour.
(2) If Carlos’s average speed for the trip had been 20 percent faster, the trip would’ve taken 3 hours.

How come the answer can be B?

This is how I am trying to do it.

Statement 1

Average speed = Total Distance/Total Time

We don't know the distance and therefore cannot calculate the time.

Statement 2

Let the initial speed be s

New speed = s + 0.2(s) = 1.2 s

1.2 S = D/T

Again as we don't know the Distance and Speed we cannot calculate the time.

But combining the 2 statement we can calculate the time. So where I have got it wrong?
[Reveal] Spoiler: OA

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Re: Time taken by Carlos [#permalink] New post 15 Mar 2012, 20:26
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Statement 1
We dont know the distance so we cannot calculate T

Statement 2
IF we apply ratios we can solve it easily.
New velocity is 1.2 (6/5) times the old velocity
i.e if velocity has increased 6/5 times then time to cover the same distance will reduce to 5/6 times.
so we can write that 5/6T(old time taken)=3(new time taken)
so T(old)=3.6 hrs

so from statement 2 we know the time taken
so the ANS is B
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Re: Time taken by Carlos [#permalink] New post 15 Mar 2012, 20:39
Hi,

I agree with jach2012.

These are those odd curve balls that gmat throws at you.
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Last edited by boomtangboy on 16 Mar 2012, 02:12, edited 1 time in total.
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Re: Time taken by Carlos [#permalink] New post 16 Mar 2012, 02:10
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How long did it take Carlos to drive nonstop from his home to Atlanta, Georgia?

Distance=Rate*Time

(1) Carlos’s average speed for the trip was 55 miles per hour --> Rate=55 miles per hour, we still need Distance to get Time. Not sufficient.

(2) If Carlos’s average speed for the trip had been 20 percent faster, the trip would’ve taken 3 hours --> notice that we are dealing with the SAME distance: Distance=Rate*Time=(1.2*Rate)*3 --> Rate*Time=(1.2*Rate)*3 --> Time=3.6 hours. Sufficient.

Answer: B.
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Re: Time taken by Carlos   [#permalink] 16 Mar 2012, 02:10
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