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How many 5 digit numbers can be created if the following

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How many 5 digit numbers can be created if the following [#permalink] New post 02 Dec 2007, 16:37
How many 5 digit numbers can be created if the following terms apply: the leftmost digit is even, the second is odd, the third is a non even prime and the fourth and fifth are two random digits not used before in the number?

a) 2520
b) 3150
c) 3360
d) 6000
e) 7500

Please Explain.
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Re: 5 Digit Number [#permalink] New post 02 Dec 2007, 18:02
Skewed wrote:
How many 5 digit numbers can be created if the following terms apply: the leftmost digit is even, the second is odd, the third is a non even prime and the fourth and fifth are two random digits not used before in the number?

a) 2520
b) 3150
c) 3360
d) 6000
e) 7500

Please Explain.


Answer should be A.

4 * 5 * 3 * 7 * 6 = 2520
__ ___ ___ ___ ___

Damn I am wrong made a small mistake.

5*5*3*7*6 = 3150

Since zero is even..so had to increase the 1st digit to 5...from 4 :)

Last edited by spider on 21 Dec 2007, 12:48, edited 1 time in total.
Re: 5 Digit Number   [#permalink] 02 Dec 2007, 18:02
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