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How many different ways can a group of 12 people be divided

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CEO
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How many different ways can a group of 12 people be divided [#permalink] New post 12 Dec 2007, 05:28
How many different ways can a group of 12 people be divided into 6 different teams of 2 people each?
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 [#permalink] New post 12 Dec 2007, 06:14
would it be...

(12*11)+(10*9)+(8*7)+(6*5)+(4*3)+(2*1)

132+90+56+30+12+2 = 322 ways

I'm not 100% confident with that answer. What's the OA?
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CEO
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 [#permalink] New post 12 Dec 2007, 07:09
Expert's post
N=12C2*10C2*8C2*6C2*4C2*2C2/6!=10395

http://www.gmatclub.com/forum/t55369
CEO
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 [#permalink] New post 12 Dec 2007, 07:33
There are going to be 6 groups. 6!

11 * 9 * 7 * 5 * 3
99 * 35 * 3
10,395

This is a variant q i made up.
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 [#permalink] New post 12 Dec 2007, 08:04
bmwhype2 wrote:
There are going to be 6 groups. 6!

11 * 9 * 7 * 5 * 3
99 * 35 * 3
10,395

This is a variant q i made up.


Is this the thought process here.

You have 12 people being split up into 6 groups and order doesn't matter (Joe and Susie = Susie + Joe)

It doesn't matter who you choose first, you have 11 choices from their partner.

Then it doesn't matter who you choose next, but you have 9 people to team up with them

etc etc

I like that way. Very simple and straight forward
  [#permalink] 12 Dec 2007, 08:04
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