|
Author |
Message |
|
TAGS:
|
|
|
Current Student
Joined: 31 Aug 2007
Posts: 374
Followers: 1
Kudos [?]:
36
[0], given: 1
|
how many different ways to seat 6 people around a circular [#permalink]
01 Aug 2008, 13:56
Question Stats:
0% (00:00) correct
0% (00:00) wrong based on 0 sessions
how many different ways to seat 6 people around a circular table if 2 of the 6 refuse to sit adjacent to one another? 96?
hmm agree 72
Last edited by young_gun on 01 Aug 2008, 16:11, edited 1 time in total.
|
|
|
|
|
|
|
Intern
Joined: 28 May 2008
Posts: 7
Followers: 0
Kudos [?]:
0
[0], given: 0
|
my guess 72 total ways = 5! = 120 pair together = 2*4! = 48 answer = 120-48 = 72
|
|
|
|
|
|
Manager
Joined: 28 Apr 2008
Posts: 114
Followers: 1
Kudos [?]:
8
[1] , given: 0
|
1
This post received KUDOS
I think it's 72
6 people can seated in 5! ways around a round table.
if 2 cant sit in ajacent seats- one of then has only 3c1 seats and te rest have 4! wayr to be seated.
we are left with 3*4!= 72 ways
|
|
|
|
|
|
Manager
Joined: 28 Jul 2004
Posts: 142
Location: Melbourne
Schools: Yale SOM, Tuck, Ross, IESE, HEC, Johnson, Booth
Followers: 1
Kudos [?]:
5
[0], given: 2
|
why does the permutation of n objects become (n-1)! in a circle?
_________________
kris
|
|
|
|
|
|
Manager
Joined: 07 Jul 2007
Posts: 139
Followers: 1
Kudos [?]:
15
[0], given: 0
|
It is because if you take for example 3 elements in circle called A, B and C then there possible arrangements in circle are only 2 instead of 6.
ABC CAB BCA
These three arrangements in circle are same....if you arrage them in circle then you will realize how it is.
|
|
|
|
|
|
Manager
Joined: 07 Jul 2007
Posts: 139
Followers: 1
Kudos [?]:
15
[0], given: 0
|
It is because if you take for example 3 elements in circle called A, B and C then there possible arrangements in circle are only 2 instead of 6.
ABC CAB BCA
These three arrangements in circle are same....if you arrage them in circle then you will realize how it is.
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|
|