lionheart187 wrote:

this is a formula for finding no of factors in such wired questions. How do you find factors of 5000^2? remember theis formula and use it.

1000^2 = (2x2x2x5x5x5)^2 = (2x5)^6

so the number of factors = (6+1)(6+1) = 49

Quick question. Why did you just find the number of factors for 1000^2 as oppossed to 5000^2 (in the original question)? Wouldn't you be missing an extra "5" thus making the number of factors = 63? -->

5000^2 = (2x2x2x5x5x5x

5)^2 = (2)^6 * (5)^8

so the number of factors = (6+1)(8+1) =

63 _________________

Factorials were someone's attempt to make math look exciting!!!