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How many five digit numbers can be formed using the digits

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Senior Manager
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How many five digit numbers can be formed using the digits [#permalink] New post 17 Jan 2004, 16:18
How many five digit numbers can be formed using the digits 0, 1, 2, 3, 4 and 5 which are divisible by 3, without repeating the digits?

(1) 15 (2) 96 (3) 216 (4) 120
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 [#permalink] New post 17 Jan 2004, 16:46
is it 216. Actually I am weak in Permu & Comb. So not sure but I did this way. of the digits 0,1,2,3,4,5 once we can use without 0 and second time without 3. So without 0 we get 120 numbers like 5*4*3*2*1=120 and without 3 we get 96 numbers like 4*4*3*2*1=96 . so 120+96=216 but not sure as my main weaknesses are Permu and comb, verbal and co-ordinate geometry.
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 [#permalink] New post 17 Jan 2004, 16:52
You got it right!!!
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Re: five digit numbers divisible by 3 [#permalink] New post 10 Jun 2012, 15:44
Can any1 please explain how come the answer is 216??

from set = {0,1,2,3,4,5}

5 digit number divisible by 3 can be formed using digits {1,2,3,4,5}, therefore 5! = 120
5 digit number divisible by 3 can be formed using digits {0,1,2,4,5}, therefore 5! = 120
therefore 240 what m i missing?
Re: five digit numbers divisible by 3   [#permalink] 10 Jun 2012, 15:44
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How many five digit numbers can be formed using the digits

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