Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: Remainder Problem [#permalink]
17 Dec 2009, 02:13

1

This post received KUDOS

Expert's post

1

This post was BOOKMARKED

zaarathelab wrote:

How many integers from 0-50 have a remainder of 3 when divided by 9?

A. 5 B 6 C 7 D 8 E 9

A remainder of 3 when divided by 9 --> \(n=9q+3\), where q is an integer \(\geq{0}\).

\(9q+3<50\) --> \(q<5\frac{2}{9}\), hence q can take 6 values from 0 to \(5\).

Answer: B (6).

Or, one can just manually list the numbers of the form \(n=9q+3\), which are less than 50: 3, 12, 21, 30, 39, and 48. Total of 6 numbers. _________________

Re: Remainder Problem [#permalink]
06 Feb 2013, 03:01

Range of numbers is 50-0+1= 51. Possible remainders= 0,1,2,3,4,5,6,7,8 51/9 gives a quotient 5 and a remainder 6. This means that after completing 5 rounds from 0 to 8 ,it found numbers with remainders from 0 to 5 and this has 1 extra count for remainder 3.Hence it is 5+1=6

Re: How many integers from 0-50 have a remainder of 3 when divid [#permalink]
08 Aug 2013, 23:12

The first number when divided by 9 leaves a remainder of 3 is 3. The last number below 50 when divided by 9 leaves a remainder of 3 is 48 so (48 - 3)/9 + 1 = 6

Re: How many integers from 0-50 have a remainder of 3 when divid [#permalink]
03 Apr 2015, 03:38

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Interested in applying for an MBA? In the fourth and final part of our live QA series with guest expert Chioma Isiadinso, co-founder of consultancy Expartus and former admissions...