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Re: Remainder Problem [#permalink]
06 Feb 2013, 03:01
Range of numbers is 50-0+1= 51. Possible remainders= 0,1,2,3,4,5,6,7,8 51/9 gives a quotient 5 and a remainder 6. This means that after completing 5 rounds from 0 to 8 ,it found numbers with remainders from 0 to 5 and this has 1 extra count for remainder 3.Hence it is 5+1=6
Re: How many integers from 0-50 have a remainder of 3 when divid [#permalink]
03 Apr 2015, 03:38
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