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How many integers from 0 to 50, inclusive, have a remainder

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Senior Manager
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New post 30 Apr 2006, 07:05
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How many integers from 0 to 50, inclusive, have a remainder of 1 when divided by 3 ?

A. 15
B. 16
C. 17
D. 18
E. 19

It an easy question, but I'm not sure in the OA.
Later explain my approach.
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New post 30 Apr 2006, 08:32
50 = 3*m +1 (Since 50 is the max value)

m max is value = 16

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New post 30 Apr 2006, 08:42
there are 16 multiples of three that are less than 50
3*16 = 48
but 1/3 = 0 remainder 1
so 17
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New post 30 Apr 2006, 08:44
kook44 wrote:
there are 16 multiples of three that are less than 50
3*16 = 48
but 1/3 = 0 remainder 1
so 17


My problem continues....I try to read the question fast and forget the stem... :oops:

It has got to be 17
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New post 30 Apr 2006, 13:42
a=1, d=3 and last term=49

49=1+(n-1)3
51/3=17=n(ANS)
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New post 01 May 2006, 00:09
OA is 17, but where do you find 1 more
as we have only 16 (from 4 to 49 inclusive)?
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New post 01 May 2006, 00:17
M8 wrote:
OA is 17, but where do you find 1 more
as we have only 16 (from 4 to 49 inclusive)?


don't forget 1, when it divides by 3, it also has a remainder of 1
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New post 02 May 2006, 05:18
Agree it is 17 :wink:
  [#permalink] 02 May 2006, 05:18
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