Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 350,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

How many integers less than 1000 have no factors(other than 1) in common with 1000 ?

a. 400 b. 399 c. 410 d. 420

First of all it should be "how many positive integers less than 1000 have no factors (other than 1) in common with 1000", as if we consider negative integers answers will be: infinitely many.

\(1000=2^3*5 ^3\) so basically we are asked to calculate the # of positive integrs less than 1000, which are not multiples of 2 or/and 5.

Multiples of 2 in the range 0-1000, not inclusive - \(\frac{998-2}{2}+1=499\); Multiples of 5 in the range 0-1000, not inclusive - \(\frac{995-5}{5}+1=199\); Multiples of both 2 and 5, so multiples of 10 - \(\frac{990-10}{10}+1=99\).

Total # of positive integers less than 1000 is 999, so # integers which are not factors of 2 or 5 equals to \(999-(499+199-99)=400\).

Yes -- we are asked to calculate the # of positive integrs less than 1000, which are not multiples of 2 or/and 5 = which done not have 2/5 as a factor.

For this we can USE the VENN diagram technique as shown below

The integers <= 1000 divigible by 2 = 1000/2 = 500, but = 499 if 1000 is excluded The integers <= 1000 divigible by 5 = 1000/5 = 200, but = 199 if 1000 is excluded The integers <= 1000 divigible by 10(2*5) = 1000/10 = 100, but = 99 if 1000 is excluded

hence, integers that r divisible by 2only and 5only = 500+200-100 (or 499+199-99 if 1000 excluded)= 600 (599 if 1000 is excluded)

Yes -- we are asked to calculate the # of positive integrs less than 1000, which are not multiples of 2 or/and 5 = which done not have 2/5 as a factor.

For this we can USE the VENN diagram technique as shown below

The integers <= 1000 divigible by 2 = 1000/2 = 500, but = 499 if 1000 is excluded The integers <= 1000 divigible by 5 = 1000/5 = 200, but = 199 if 1000 is excluded The integers <= 1000 divigible by 10(2*5) = 1000/10 = 100, but = 99 if 1000 is excluded

hence, integers that r divisible by 2only and 5only = 500+200-100 (or 499+199-99 if 1000 excluded)= 600 (599 if 1000 is excluded)

so the answer is 1000-600 (or 999 - 599) = 400.

am i correct.

Yes, it's correct. Basically the same way as used in my post. _________________

Bunuel, why can't we simply divide 1000 by 2 to find the number of multiples of 2? My reasoning is that every second number is a multiple of 2 so there must be exactly 500 numbers.

Bunuel, why can't we simply divide 1000 by 2 to find the number of multiples of 2? My reasoning is that every second number is a multiple of 2 so there must be exactly 500 numbers.

Thanks.

There are 100/2=500 multiple of 2 in the range 1-1000 INCLUSIVE. As we need numbers LESS than 1000 which are also multiples of 2 then we should subtract 1 from that number. So there are total of 500-1=499 multiples of 2 in the range 0-1000, not inclusive. _________________

Hi! I have a book with this question and it says, that the correct answer 401...i see that there is no such answers in your questions...so i really confused..can somebody explain why it can be 401? or it is a 100% mistake?

Re: How many integers less than 1000 have no factors (other than [#permalink]
07 Jan 2013, 11:18

The question asks for the number of integers less than 1000 and other than 1. Isnt one included in the 400 integers that you are claimimg to be the answer? Answer should be 399 if we exclude 1. Please correct me in case i missed something.

Re: How many integers less than 1000 have no factors (other than [#permalink]
07 Jan 2013, 19:54

1

This post received KUDOS

Expert's post

rohantiwari wrote:

The question asks for the number of integers less than 1000 and other than 1. Isnt one included in the 400 integers that you are claimimg to be the answer? Answer should be 399 if we exclude 1. Please correct me in case i missed something.

The question does not ask you to exclude 1.

Every positive integer less than 1000 has one common factor with 1000. What is it? It is 1. 1 is a common factor between any two positive integers.

If the question were: How many positive integers less than 1000 have no factors in common with 1000 ? Then the answer would be 0. There are no positive integers which have no common factors with 1000. All the positive integers have a common factor and that is 1. But the question wants to know the number of positive integers which have no common factor other than 1 (1 will always be a common factor). Basically, it is looking for positive integers which are co-prime with 1000. _________________

Re: How many integers less than 1000 have no factors (other than [#permalink]
02 Apr 2013, 11:30

consider integers between 1 and 100 - half of them are even - hence 50 integers are multiples of 2 ( which also includes even multiples of 5) + 10 odd multiples of 5 = 60 Hence 40 integers that are not multiples of 2 and/or 5 - hence considering integers between 1 and 1000 - there are 40*10 = 400 integers which do not have common multiple with 1000 other than 1. _________________

How many integers less than 1000 have no factors(other than 1) in common with 1000 ?

a. 400 b. 399 c. 410 d. 420

First of all it should be "how many positive integers less than 1000 have no factors (other than 1) in common with 1000", as if we consider negative integers answers will be: infinitely many.

\(1000=2^3*5 ^3\) so basically we are asked to calculate the # of positive integrs less than 1000, which are not multiples of 2 or/and 5.

Multiples of 2 in the range 0-1000, not inclusive - \(\frac{998-2}{2}+1=499\); Multiples of 5 in the range 0-1000, not inclusive - \(\frac{995-5}{5}+1=199\); Multiples of both 2 and 5, so multiples of 10 - \(\frac{990-10}{10}+1=99\).

Total # of positive integers less than 1000 is 999, so # integers which are not factors of 2 or 5 equals to \(999-(499+199-99)=400\).

Answer: A.

What about the prime numbers Bunuel ?? For ex : 7. Neither its a multiple of 2, nor 5 and it does not has any common factors with 1000 (except 1) So, shouldn't the answer include prime numbers between 1-999 as well. And if YES, how do we calculate the number of primer numbers from 1-999 ??? Plz clarfily.

How many integers less than 1000 have no factors (other than 1) in common with 1000 ?

a. 400 b. 399 c. 410 d. 420

First of all it should be "how many positive integers less than 1000 have no factors (other than 1) in common with 1000", as if we consider negative integers answers will be: infinitely many.

\(1000=2^3*5 ^3\) so basically we are asked to calculate the # of positive integrs less than 1000, which are not multiples of 2 or/and 5.

Multiples of 2 in the range 0-1000, not inclusive - \(\frac{998-2}{2}+1=499\); Multiples of 5 in the range 0-1000, not inclusive - \(\frac{995-5}{5}+1=199\); Multiples of both 2 and 5, so multiples of 10 - \(\frac{990-10}{10}+1=99\).

Total # of positive integers less than 1000 is 999, so # integers which are not factors of 2 or 5 equals to \(999-(499+199-99)=400\).

Answer: A.

What about the prime numbers Bunuel ?? For ex : 7. Neither its a multiple of 2, nor 5 and it does not has any common factors with 1000 (except 1) So, shouldn't the answer include prime numbers between 1-999 as well. And if YES, how do we calculate the number of primer numbers from 1-999 ??? Plz clarfily.

Thanks.

We counted multiples of 2 or 5 in the range 0-1000, not inclusive and then subtracted that from total number of integers in the range 0-1000. The number we get contains all numbers which are not multiples of 2 or 5, thus all primes (apart from 2 and 5) in that range too.

Re: How many integers less than 1000 have no factors (other than [#permalink]
28 Oct 2014, 12:18

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Hey, everyone. After a hectic orientation and a weeklong course, Managing Groups and Teams, I have finally settled into the core curriculum for Fall 1, and have thus found...

MBA Acceptance Rate by Country Most top American business schools brag about how internationally diverse they are. Although American business schools try to make sure they have students from...

For the past couple of weeks I’ve been winding down my affairs in New York by working on consulting projects, trying every exotic sandwich there is and then intensely...