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how many integers n such that r<n<s? (1) s-r =5 (2) R

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how many integers n such that r<n<s? (1) s-r =5 (2) R [#permalink]

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19 Aug 2003, 20:20
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how many integers n such that r<n<s?

(1) s-r =5
(2) R and S are not integers.

can someone explain how to tackle such questions.
would appreciate it
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Joined: 23 Jun 2003
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19 Aug 2003, 21:06
doloris wrote:
how many integers n such that r<n<s?

(1) s-r =5
(2) R and S are not integers.

can someone explain how to tackle such questions.
would appreciate it

(1) If s and r are both real numbers (non-integers), n will equal 5. If s and r are both integers, n will equal 4. Therefore, insufficient.

(2) Insufficient since R and S could be anything

Combined, 1 and 2 give us all we need... we know how many values for n exist (5). Answer = C
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20 Aug 2003, 05:16
i do not understand.
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20 Aug 2003, 07:31
doloris wrote:
i do not understand.

Try plugging in numbers.
For A you must have numbers that are 5 apart. so lets use 10 and 5. we have 6,7,8,9. that is four numbers. now, since the question stem does not say that the numbers must be integers, try 10.5 and 5.5. now we have 6,7,8,9,10. thats five different integers. this is not suff

For B, alone, this tells us nothing. It could be the number of integers between 675.463 and 345674, or it could be 1 and 1.1. This tells us nothing alone.

Now combine the two. Remember from part 1 when we tried the non-integers. So any numbers that are 5 apart, but are not integers will always have five integers between them.Sufficient
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20 Aug 2003, 22:46
hi! thanks so much for the explanation.things are much clearer now.

regards
20 Aug 2003, 22:46
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