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How many liters of a solution that is 15% salt must be added [#permalink]
09 Oct 2006, 16:55

How many liters of a solution that is 15% salt must be added to 5 liters of a solution that is 8% salt so that the resulting solution is 10% salt?

Solution:
Let n represent the number of liters of the 15% solution. The amount of salt in the 15% solution [0.15n] plus the amount of salt in the 8% solution [(0.08)(5)] must be equal to the amount of salt in the 10% mixture [0.10 (n + 5)].

.15n + .08(5) = .10(n+5)

Answer: n = 2

Can someone help me understand the .10(n+5) part? Any help is appreciated.

based on Cicerone's technique..wouldn't the following solution be 2?.. I got this question from an earlier post, and apparently the OA is D? Can someone explain?

How many gallons of water must be mixed with 1 gallon of a 15% salt soltion to obtain a 10% salt solution?
A)0.5
B)0.67
C)1.0
D)1.5
E) 2.0

based on Cicerone's technique..wouldn't the following solution be 2?.. I got this question from an earlier post, and apparently the OA is D? Can someone explain?

How many gallons of water must be mixed with 1 gallon of a 15% salt soltion to obtain a 10% salt solution? A)0.5 B)0.67 C)1.0 D)1.5 E) 2.0

hey, the answer will be o.5. I guess u made a silly mistake.......
Look at this

Originally posted on MIT Sloan School of Management : We are busy putting the final touches on our application. We plan to have it go live by July 15...