How many more men than women are in the room? : DS Archive
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 23 Jan 2017, 22:50

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# How many more men than women are in the room?

Author Message
Manager
Joined: 05 Sep 2007
Posts: 144
Location: New York
Followers: 1

Kudos [?]: 36 [0], given: 0

How many more men than women are in the room? [#permalink]

### Show Tags

20 Sep 2007, 09:37
00:00

Difficulty:

(N/A)

Question Stats:

100% (01:05) correct 0% (00:00) wrong based on 8 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.
VP
Joined: 09 Jul 2007
Posts: 1104
Location: London
Followers: 6

Kudos [?]: 103 [0], given: 0

### Show Tags

20 Sep 2007, 11:49
el1981 wrote:
How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.

it is C.

1. m+w=20 we do not know how many of men and women separately

2. from the statement 2 we know that M=W^2 it can be M=16 and W=4

so C
Manager
Joined: 05 Sep 2007
Posts: 144
Location: New York
Followers: 1

Kudos [?]: 36 [0], given: 0

### Show Tags

20 Sep 2007, 12:04
Ravshonbek wrote:
el1981 wrote:
How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.

it is C.

1. m+w=20 we do not know how many of men and women separately

2. from the statement 2 we know that M=W^2 it can be M=16 and W=4

so C

I got it. I made a mistake by substituting m=w^2 into m+w=20.
Thanks a lot.
Director
Joined: 11 Jun 2007
Posts: 931
Followers: 1

Kudos [?]: 175 [0], given: 0

### Show Tags

20 Sep 2007, 17:16
el1981 wrote:
Ravshonbek wrote:
el1981 wrote:
How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.

it is C.

1. m+w=20 we do not know how many of men and women separately

2. from the statement 2 we know that M=W^2 it can be M=16 and W=4

so C

I got it. I made a mistake by substituting m=w^2 into m+w=20.
Thanks a lot.

you did it right. if you combine the two stmts it would be:
m + w = 20
w^2 + w = 20
w^2 + w - 20 = 0
(w + 5) (w - 4)
w = -5, 4
cannot be -5 women so the only logical answer is 4
so plugging back into first eqn it would be
m + 4 = 20
m = 16, w = 4

you'll see that these solutions also work for the second eqn
w = 4, w^2 = 16
VP
Joined: 10 Jun 2007
Posts: 1459
Followers: 7

Kudos [?]: 256 [0], given: 0

### Show Tags

20 Sep 2007, 17:19
el1981 wrote:
How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.

Straight C
two equations two unknowns from (1) and (2), no need to solve
m+w=20
m=w^2
CEO
Joined: 29 Mar 2007
Posts: 2583
Followers: 19

Kudos [?]: 422 [0], given: 0

### Show Tags

20 Sep 2007, 19:33
el1981 wrote:
How many more men than women are in the room?
1. There is a total of 20 women and men in the room.
2. The number of men in the room equals the square of the number of women in the room.

Ans should be C.

S1: w+m=20. Can't find value of either from here without more info.

S2: m=w^2. We know the relationship of m to w, but cannot establish actual values b/c we don't know the total number of men and women.

Ex/ if m=4 w=2. Total is 6. But also could be: m=16 w=4. Total is 20. So not suff.

Together we know the relationship and we have the total value of w and m.

So if m=w^2, plug it in. w^2+w=20---> w^2+w-20=0 (w+5)(w-4)=0 ---> w=-5 or 4. We can't have negative women so value of women is 4.

Thus value of men is 16 so there are 12 more men that women in the room.
Re: DS   [#permalink] 20 Sep 2007, 19:33
Display posts from previous: Sort by