Find all School-related info fast with the new School-Specific MBA Forum

It is currently 19 Sep 2014, 00:17

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Events & Promotions

Events & Promotions in June
Open Detailed Calendar

How many of the factors of 72 are divisible by 2?

  Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:
Manager
Manager
User avatar
Joined: 07 Jan 2010
Posts: 147
Location: So. CA
WE 1: 2 IT
WE 2: 4 Software Analyst
Followers: 2

Kudos [?]: 11 [0], given: 57

GMAT Tests User
How many of the factors of 72 are divisible by 2? [#permalink] New post 08 Sep 2010, 21:58
2
This post was
BOOKMARKED
00:00
A
B
C
D
E

Difficulty:

  55% (hard)

Question Stats:

51% (01:47) correct 49% (00:47) wrong based on 172 sessions
How many of the factors of 72 are divisible by 2?

A. 4
B. 5
C. 6
D. 8
E. 9

m12 #19

What is the quickest and fastest way to find all factors of 72? I drew a prime factor tree but missed some factors in the process. :(
[Reveal] Spoiler: OA
Expert Post
2 KUDOS received
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 23471
Followers: 3500

Kudos [?]: 26400 [2] , given: 2710

Re: m12 #19 How many of the factors of 72 [#permalink] New post 08 Sep 2010, 22:09
2
This post received
KUDOS
Expert's post
gtr022001 wrote:
How many of the factors of 72 are divisible by 2?
a. 4
b. 5
c. 6
d. 8
e. 9


What is the quickest and fastest way to find all factors of 72? I drew a prime factor tree but missed some factors in the process. :(


FIRST:

Finding the Number of Factors of an Integer

First make prime factorization of an integer n=a^p*b^q*c^r, where a, b, and c are prime factors of n and p, q, and r are their powers.

The number of factors of n will be expressed by the formula (p+1)(q+1)(r+1). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: 450=2^1*3^2*5^2

Total number of factors of 450 including 1 and 450 itself is (1+1)*(2+1)*(2+1)=2*3*3=18 factors.

BACK TO THE ORIGINAL QUESTION:

According to the above as 72=2^3*3^2, then # of factors of 72 is (3+1)(2+1)=12. Out of which only 3 are odd 1, 3, and 9, so rest or 12-3=9 are even.

OR: as 72=2^3*3^2 then even factors MUST have 2 either in power of 1, 2, or 3 so 3 options and 3 either in power 0, 1, or 2 again 3 options --> 3*3=9.

Answer: E.

Hope it helps.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership


Last edited by Bunuel on 08 Sep 2010, 23:11, edited 1 time in total.
Intern
Intern
avatar
Joined: 08 Oct 2012
Posts: 32
Followers: 1

Kudos [?]: 5 [0], given: 24

How many of the factors of 72 are divisible by 2? [#permalink] New post 19 Nov 2012, 21:21
How many of the factors of 72 are divisible by 2?
A. 4
B. 5
C. 6
D. 8
E. 9

I got it right, but I would like to know if my method is efficient.

72 = 2*2*2*3*3
therefore, different numbers that can be found from the above = 5!/3!*2! = 10
Out of these 10, only one number (3*3) is odd....hence, the answer is 10-1 = 9.
3 KUDOS received
VP
VP
avatar
Joined: 23 Mar 2011
Posts: 1092
Followers: 72

Kudos [?]: 444 [3] , given: 452

Premium Member CAT Tests
Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 19 Nov 2012, 22:01
3
This post received
KUDOS
kapsycumm wrote:
How many of the factors of 72 are divisible by 2?
A. 4
B. 5
C. 6
D. 8
E. 9

I got it right, but I would like to know if my method is efficient.

72 = 2*2*2*3*3
therefore, different numbers that can be found from the above = 5!/3!*2! = 10
Out of these 10, only one number (3*3) is odd....hence, the answer is 10-1 = 9.


you were lucky there :) I'm afraid the method is incorrect.

Sol:

The number of factors of 72 will be 12 and not 10. The best way to find out is if X= a^b * c^d then number of factors are (b+1) * (d+1)

here 72= 2^3*3^2 so number of factors will be (3+1) * (2+1) = 12 --> this includes 1 and the number itself.

so for finding factors not divisible by 2, remove all the 2s from the prime factorization. You will be left with 3^2.

so factors will be 3 and 3^2(=9). Also, we need to include the number 1 to this list, as it is odd and not divisible by 2.

so 12-3=9

the flaw in your approach:
1.) 5!/2!*3! will give you the number of ways you can arrange (permute) 22233. essentially it gives you the following list:
22233,22323,33222,32322 etc. As you can see this is a mere representation of how you can write three 2s and two 3s. This does NOT give you the list of factors of 72.
2.) not only 3*3 is odd but 3 and 3*3 both are odd factors. Include 1 to this list and you get the 3 odd factors.


hope this helps.
_________________

My Debrief | MBA Timeline - New! Stay on top of deadlines, receive recommendations for each stage, get reminders.

1 KUDOS received
Intern
Intern
avatar
Joined: 20 Oct 2012
Posts: 5
Followers: 0

Kudos [?]: 3 [1] , given: 2

Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 19 Nov 2012, 22:19
1
This post received
KUDOS
kapsycumm wrote:
How many of the factors of 72 are divisible by 2?
A. 4
B. 5
C. 6
D. 8
E. 9

I got it right, but I would like to know if my method is efficient.

72 = 2*2*2*3*3
therefore, different numbers that can be found from the above = 5!/3!*2! = 10
Out of these 10, only one number (3*3) is odd....hence, the answer is 10-1 = 9.


I'm with the poster above - think you were lucky on this one.

A quick check (good thing listing factors of 72 doesn't take long):
Factors - (12) 1, 2, 3, 4, 6, 8, 9, 12, 18, 24, 36, 72
Factors NOT divisible by 2 - (3) 1, 3, 9

Therefore answer is 12 - 3 = 9.
Intern
Intern
avatar
Joined: 20 Oct 2012
Posts: 5
Followers: 0

Kudos [?]: 3 [0], given: 2

Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 19 Nov 2012, 22:27
jumsumtak wrote:
kapsycumm wrote:
How many of the factors of 72 are divisible by 2?
A. 4
B. 5
C. 6
D. 8
E. 9

I got it right, but I would like to know if my method is efficient.

72 = 2*2*2*3*3
therefore, different numbers that can be found from the above = 5!/3!*2! = 10
Out of these 10, only one number (3*3) is odd....hence, the answer is 10-1 = 9.


you were lucky there :) I'm afraid the method is incorrect.

Sol:

The number of factors of 72 will be 12 and not 10. The best way to find out is if X= a^b * c^d then number of factors are (b+1) * (d+1)

here 72= 2^3*3^2 so number of factors will be (3+1) * (2+1) = 12 --> this includes 1 and the number itself.

so for finding factors not divisible by 2, remove all the 2s from the prime factorization. You will be left with 3^2.

so factors will be 3 and 3^2(=9). Also, we need to include the number 1 to this list, as it is odd and not divisible by 2.

so 12-3=9

the flaw in your approach:
1.) 5!/2!*3! will give you the number of ways you can arrange (permute) 22233. essentially it gives you the following list:
22233,22323,33222,32322 etc. As you can see this is a mere representation of how you can write three 2s and two 3s. This does NOT give you the list of factors of 72.
2.) not only 3*3 is odd but 3 and 3*3 both are odd factors. Include 1 to this list and you get the 3 odd factors.


hope this helps.



BTW - jumsumtak actually shows you how to find the number of factors for a number, and will be a time saver in the exam. Note the example here works with only two prime factors. For another example with three prime factors: "How many factors in 360?", 360 = 5 x 8 x 9 --> (1+1) x (3+1) x (2+1) = 24.
VP
VP
avatar
Joined: 23 Mar 2011
Posts: 1092
Followers: 72

Kudos [?]: 444 [0], given: 452

Premium Member CAT Tests
Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 19 Nov 2012, 22:59
jcaine wrote:

BTW - jumsumtak actually shows you how to find the number of factors for a number, and will be a time saver in the exam. Note the example here works with only two prime factors. For another example with three prime factors: "How many factors in 360?", 360 = 5 x 8 x 9 --> (1+1) x (3+1) x (2+1) = 24.



That is correct. This works with every number not with just 2 prime factors. you can have 'n' PRIME factors and it will still hold true.

360 = 5 x 8 x 9 = 5 x 2^3 x 3^2. So the factors will be (1+1) x (3+1) x ( 2+1) = 2 x 4 x 3= 24
_________________

My Debrief | MBA Timeline - New! Stay on top of deadlines, receive recommendations for each stage, get reminders.

Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 23471
Followers: 3500

Kudos [?]: 26400 [0], given: 2710

Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 20 Nov 2012, 02:30
Expert's post
kapsycumm wrote:
How many of the factors of 72 are divisible by 2?
A. 4
B. 5
C. 6
D. 8
E. 9

I got it right, but I would like to know if my method is efficient.

72 = 2*2*2*3*3
therefore, different numbers that can be found from the above = 5!/3!*2! = 10
Out of these 10, only one number (3*3) is odd....hence, the answer is 10-1 = 9.


Merging similar topics. Please refer to the solutions above.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Manager
Manager
avatar
Joined: 05 Nov 2012
Posts: 151
Followers: 1

Kudos [?]: 9 [0], given: 56

Re: m12 #19 How many of the factors of 72 [#permalink] New post 20 Nov 2012, 07:03
Bunuel wrote:
gtr022001 wrote:
How many of the factors of 72 are divisible by 2?
a. 4
b. 5
c. 6
d. 8
e. 9


What is the quickest and fastest way to find all factors of 72? I drew a prime factor tree but missed some factors in the process. :(


FIRST:

Finding the Number of Factors of an Integer

First make prime factorization of an integer n=a^p*b^q*c^r, where a, b, and c are prime factors of n and p, q, and r are their powers.

The number of factors of n will be expressed by the formula (p+1)(q+1)(r+1). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: 450=2^1*3^2*5^2

Total number of factors of 450 including 1 and 450 itself is (1+1)*(2+1)*(2+1)=2*3*3=18 factors.

BACK TO THE ORIGINAL QUESTION:

According to the above as 72=2^3*3^2, then # of factors of 72 is (3+1)(2+1)=12. Out of which only 3 are odd 1, 3, and 9, so rest or 12-3=9 are even.

OR: as 72=2^3*3^2 then even factors MUST have 2 either in power of 1, 2, or 3 so 3 options and 3 either in power 0, 1, or 2 again 3 options --> 3*3=9.

Answer: E.

Hope it helps.

number of factors and prime factors is fine.... but out of those number of factors... how did you conclude on as only 3 being odd?
Intern
Intern
avatar
Joined: 20 Oct 2012
Posts: 5
Followers: 0

Kudos [?]: 3 [0], given: 2

Re: m12 #19 How many of the factors of 72 [#permalink] New post 24 Nov 2012, 20:20
Amateur wrote:
number of factors and prime factors is fine.... but out of those number of factors... how did you conclude on as only 3 being odd?



(Will try to explain this using an easier but slightly slower approach since many have difficulties grasping perms & combs)

Using the number 72 from the original question;
[1] Find number of factors:
1. 72 = 2^3 x 3^2;
2. therefore number of factors = (3+1) x (2+1) = 12

[2] Find number of ODD factors:
*Number property, N1: We know that all primes, except 2, are odd.
*Number property, N2: We know that ODD x ODD = ODD.
*Number property, N3: Multiplying any number by 2 (an Even Number) will yield an EVEN number.

1. Recalling from [1], we have identified 2 and 3 as the prime factors of 72.
2. We ignore the "2" remembering N3.
3. We can construct factors that consist of prime factor 3 only:3, 3 x 3 (since there are only two "3"s we stop here).
4. Let's not forget that "1" is also a non-even factor.
5. Total of ODD factors is 3.

[3] Find number of EVEN factors: Total of factors - total of odd factors = total of even factors = 12 - 3 = 9.


One could directly use combinations of 2, 2, 2, 3, 3 to list all EVEN factors but I've found it faster to find ODD factors first.

For example, in my explanation for counting factors for a number with three distinct primes:
1. 360 = 5 x 8 x 9 = 5^1 x 2^3 x 3^2
2. Number of primes = (1+1) x (3+1) x (2+1) = 24
3. Number of odd factors will be multiples of only up to 1 "5" and 2 "3"s.
4. List odd factors:
3
5
9 = 3 x 3
15 = 3 x 5
45 = 3 x 3 x 5
5. Do not forget that "1" is also a factor, therefore there are 6 ODD factors in 360.
6. Total of EVEN factors in 360 is 24 - 6 = 18.

*Quick Check with pairs indeed reveals 6 ODD factors:
1, 360 --> 1 is ODD
2, 180
3, 120 --> 3 is ODD
4, 90
5, 72 --> 5 is ODD
6, 60
8, 45 --> 45 is ODD
9, 40 --> 9 is ODD
10, 36
12, 30
15, 24 --> 15 is ODD
18, 20


Hope this clarifies things.
* Do note that I would expect 750+ questions to involve combinatorics that involve the use of perms & combs to solve within the time limit.
Manager
Manager
User avatar
Joined: 14 Jan 2013
Posts: 158
Concentration: Strategy, Technology
GMAT Date: 08-01-2013
GPA: 3.7
WE: Consulting (Consulting)
Followers: 2

Kudos [?]: 51 [0], given: 29

Re: m12 #19 How many of the factors of 72 [#permalink] New post 07 Mar 2014, 19:27
Bunuel wrote:
gtr022001 wrote:
How many of the factors of 72 are divisible by 2?
a. 4
b. 5
c. 6
d. 8
e. 9


What is the quickest and fastest way to find all factors of 72? I drew a prime factor tree but missed some factors in the process. :(


FIRST:

Finding the Number of Factors of an Integer

First make prime factorization of an integer n=a^p*b^q*c^r, where a, b, and c are prime factors of n and p, q, and r are their powers.

The number of factors of n will be expressed by the formula (p+1)(q+1)(r+1). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: 450=2^1*3^2*5^2

Total number of factors of 450 including 1 and 450 itself is (1+1)*(2+1)*(2+1)=2*3*3=18 factors.

BACK TO THE ORIGINAL QUESTION:

According to the above as 72=2^3*3^2, then # of factors of 72 is (3+1)(2+1)=12. Out of which only 3 are odd 1, 3, and 9, so rest or 12-3=9 are even.

OR: as 72=2^3*3^2 then even factors MUST have 2 either in power of 1, 2, or 3 so 3 options and 3 either in power 0, 1, or 2 again 3 options --> 3*3=9.

Answer: E.

Hope it helps.


Bunuel,

how do we know the red part without writing all the factors of 72?
_________________

"Where are my Kudos" ............ Good Question = kudos

"Start enjoying all phases" & all Sections

__________________________________________________________________
http://gmatclub.com/forum/collection-of-articles-on-critical-reasoning-159959.html

percentages-700-800-level-questions-130588.html

700-to-800-level-quant-question-with-detail-soluition-143321.html

Expert Post
Math Expert
User avatar
Joined: 02 Sep 2009
Posts: 23471
Followers: 3500

Kudos [?]: 26400 [0], given: 2710

Re: m12 #19 How many of the factors of 72 [#permalink] New post 08 Mar 2014, 05:45
Expert's post
Mountain14 wrote:
Bunuel wrote:
gtr022001 wrote:
How many of the factors of 72 are divisible by 2?
a. 4
b. 5
c. 6
d. 8
e. 9


What is the quickest and fastest way to find all factors of 72? I drew a prime factor tree but missed some factors in the process. :(


FIRST:

Finding the Number of Factors of an Integer

First make prime factorization of an integer n=a^p*b^q*c^r, where a, b, and c are prime factors of n and p, q, and r are their powers.

The number of factors of n will be expressed by the formula (p+1)(q+1)(r+1). NOTE: this will include 1 and n itself.

Example: Finding the number of all factors of 450: 450=2^1*3^2*5^2

Total number of factors of 450 including 1 and 450 itself is (1+1)*(2+1)*(2+1)=2*3*3=18 factors.

BACK TO THE ORIGINAL QUESTION:

According to the above as 72=2^3*3^2, then # of factors of 72 is (3+1)(2+1)=12. Out of which only 3 are odd 1, 3, and 9, so rest or 12-3=9 are even.

OR: as 72=2^3*3^2 then even factors MUST have 2 either in power of 1, 2, or 3 so 3 options and 3 either in power 0, 1, or 2 again 3 options --> 3*3=9.

Answer: E.

Hope it helps.


Bunuel,

how do we know the red part without writing all the factors of 72?


It's not hard to find the number of odd factors of 72 manually but if you want more systematic approach, refer to the red part above or consider the following:

Get rid of all the 2’s which give even factors in 72, so divide 72 by 2^3=8: 72/2^3=9=3^2. Now, 9 will have all the odd factors of 72 and won’t have its even factors. The number of factors of 9 is (2+1)=3.

So, we know that 72 has total of 12 factors out of which 3 are odd. Therefore 72 has 12-3=9 even factors.

Hope it's clear.
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


What are GMAT Club Tests?
25 extra-hard Quant Tests

Get the best GMAT Prep Resources with GMAT Club Premium Membership

Manager
Manager
User avatar
Joined: 14 Jan 2013
Posts: 158
Concentration: Strategy, Technology
GMAT Date: 08-01-2013
GPA: 3.7
WE: Consulting (Consulting)
Followers: 2

Kudos [?]: 51 [0], given: 29

Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 10 Mar 2014, 04:06
Yes , it clear... thanks
_________________

"Where are my Kudos" ............ Good Question = kudos

"Start enjoying all phases" & all Sections

__________________________________________________________________
http://gmatclub.com/forum/collection-of-articles-on-critical-reasoning-159959.html

percentages-700-800-level-questions-130588.html

700-to-800-level-quant-question-with-detail-soluition-143321.html

1 KUDOS received
Manager
Manager
avatar
Joined: 13 Aug 2012
Posts: 114
Followers: 0

Kudos [?]: 17 [1] , given: 105

CAT Tests
Re: How many of the factors of 72 are divisible by 2? [#permalink] New post 25 Mar 2014, 08:03
1
This post received
KUDOS
ANOTHER METHOD
Just count the no of different factors 72 has

1x72
2x36
3x24
4x18
6x12
9x8
Now of of these - 2,4,6,72,36,24,18,12 and 8 are factors divisible by 2 i.e a total of 9 factors.
Did not take more than a minute.
Re: How many of the factors of 72 are divisible by 2?   [#permalink] 25 Mar 2014, 08:03
    Similar topics Author Replies Last post
Similar
Topics:
10 Experts publish their posts in the topic If N=2^7*3^5*5^6*7^8. How many factors of N are divisible by GMATtracted 7 05 May 2013, 10:38
If m is divisible by 3, how many prime factors does m have? vivektripathi 7 20 Sep 2008, 09:44
Experts publish their posts in the topic How many of the factors of 72 are divisible by 2? 4 5 6 bmwhype2 5 21 Nov 2007, 07:07
If m is divisible by 3, how many prime factors does m have? johnycute 8 04 Jan 2007, 22:44
If m is divisible by 3, how many prime factors does m have? jamesrwright3 3 10 Aug 2006, 19:03
Display posts from previous: Sort by

How many of the factors of 72 are divisible by 2?

  Question banks Downloads My Bookmarks Reviews Important topics  


GMAT Club MBA Forum Home| About| Privacy Policy| Terms and Conditions| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group and phpBB SEO

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.