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# How many ounces of a 60% salt solution must be added to 50

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How many ounces of a 60% salt solution must be added to 50 [#permalink]

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16 Dec 2012, 23:03
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How many ounces of a 60% salt solution must be added to 50 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt?

A. 16.67
B. 30
C. 50
D. 60.33
E. 70

I have the algebraic solution in front of me (and will post if anyone cares)

But I was wondering if there was a more intuitive, easy or plugging in way of solving this.
[Reveal] Spoiler: OA

Last edited by Bunuel on 16 Dec 2012, 23:07, edited 1 time in total.
Edited the question and tags.
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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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16 Dec 2012, 23:10
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anon1 wrote:
How many ounces of a 60% salt solution must be added to 50 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt?

A. 16.67
B. 30
C. 50
D. 60.33
E. 70

I have the algebraic solution in front of me (and will post if anyone cares)

But I was wondering if there was a more intuitive, easy or plugging in way of solving this.

For 60% salt solution (X) and 20% salt solution (Y) to give 40%=(60+20)/2 salt solution, we should mix equal amounts of X and Y.

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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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16 Dec 2012, 23:15
Wow, that was pcretty eassy...

Bunuel, a couple of questions. #1 what if the numbers had not been perfectly in the middle like that?

What if the prompt had asked for a solution of 32% salt?

(would this even ever happen on the GMAT?)

And #2 , how were you able to recognize that? Are you just a genius like that or was there something in particular that caught your eye, either in regards to recognizing patterns or the nature of GMAT questions.?
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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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19 Feb 2013, 22:59
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We can do this by alligation method as well

60 20

40

60 - 40 = 20 & 40 - 20 = 20
; 20:20 = 1:1... it should be mixed in equal amounts ie. 50 ounces
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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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12 Jan 2015, 15:24
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Assume original solution = 100 oz @60% concentration:
Amount of salt = 60 oz

In 50 oz solution @ 20% concentration:
Amount of salt = 10 oz

Assume, we need 100 oz @ 40% concentration:
Let X = Amount of 60 oz solution we need for mixing.

Therefore, the equation is:
10 oz + 60X oz = 40 oz
X = 0.5 i.e. 50% or half of the solution

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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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02 Apr 2016, 15:31
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Re: How many ounces of a 60% salt solution must be added to 50 [#permalink]

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31 Jul 2016, 16:41
let x=ounces of 60% salt solution to be added
.2*50+.6x=.4(50+x)
x=50
Re: How many ounces of a 60% salt solution must be added to 50   [#permalink] 31 Jul 2016, 16:41
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# How many ounces of a 60% salt solution must be added to 50

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