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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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First girl can on a date with 3 boys
Second girl can on a date with 2 boys
Third girl can go on a date with 1 boy
Number of possible ways = 3*2*1
=6
Answer D
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How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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genxer123 wrote:
Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?



Someone, please answer this. even I had to read the question two times just to cross-check.
Although this question favors 6 and I completely get it why, but I think a slight word play in question can actually create 9 the right answer.
Would love to see how both the questions look like side by side.

Any experts hear this?
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
Inten21 wrote:
genxer123 wrote:
Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?



Someone, please answer this. even I had to read the question two times just to cross-check.
Although this question favors 6 and I completely get it why, but I think a slight word play in question can actually create 9 the right answer.
Would love to see how both the questions look like side by side.

Any experts hear this?


I too have the same doubt

BrentGMATPrepNow - Request your support
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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Pritishd wrote:
Inten21 wrote:
genxer123 wrote:
Bunuel wrote:
How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a date with 3 boys (Peter, Kyle, Sam)?

(A) 3
(B) 4
(C) 5
(D) 6
(E) 8
Bunuel , in the phrasing of the question, what should tell me that I should not use 3*3?

I interpreted the question to be asking: how many ways can each girl go on a date with each boy, i.e., how many ways can we make pairs of girl-with-boy?

Let girls = A, B, and C. Let boys = 1, 2, and 3. We can have

A <-> 1 | A <-> 2 | A <-> 3
B <-> 2 | B <-> 3 | B <-> 1
C <-> 3 | C <-> 1 | C <-> 2

That's 9. Not an answer choice. I chose 6 because it's a multiple of 2 and 3. I got lucky.

So I'm confused: what's mistaken about my assumptions and/or my method? What should have signaled me that the question meant "If one girl gets to pick first on one night . . ."?



Someone, please answer this. even I had to read the question two times just to cross-check.
Although this question favors 6 and I completely get it why, but I think a slight word play in question can actually create 9 the right answer.
Would love to see how both the questions look like side by side.

Any experts hear this?


I too have the same doubt

BrentGMATPrepNow - Request your support


The wording is a little ambiguous since there's nothing that suggests two girls can't both date the same boy (on different nights).
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How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
“How many possible ways can 3 girls go on a date with 3 boys”

I interpreted the sentence to mean that all 3 girls and all 3 boys go on one date. How many ways can this one date occur.

Easiest way would be to List the various ways we could pair a girl with a boy such that each gets paired with one.

Girls: A, B, C

Boys: 1, 2, 3

A -1:

B can go with 2 ——- and C can go with 3
Or
B can go with 3 —— and C can go with 2

2 possibilities


A-2

2 more possibilities

A-3

2 more possibilities


2 + 2 + 2 = 6



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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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Re: How many possible ways can 3 girls (Rebecca, Kate, Ashley) go on a dat [#permalink]
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