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How many pounds of salt at 50 cents/lb must be mixed

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How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 07 Aug 2012, 13:26
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Question Stats:

64% (02:33) correct 35% (01:50) wrong based on 1 sessions
How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?

A) 20
B) 15
C) 40
D) 50
E) 25

Source: 4gmat
[Reveal] Spoiler: OA

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Re: How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 07 Aug 2012, 14:23
I would do it this way:

1,2(50x + 40*35 / x+40) = 48

Solve for x = 20, so it's A. The path is quite long, maybe somehone has some shortcuts.
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Re: How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 07 Aug 2012, 21:59
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SOURH7WK wrote:
How many pounds of salt at 50 cents/lb must be mixed with 40 lbs of salt that costs 35 cents/lb so that a merchant will get 20% profit by selling the mixture at 48 cents/lb?

A) 20
B) 15
C) 40
D) 50
E) 25

Source: 4gmat


Selling price is 48 cents/lb
For a 20% profit, cost price should be 40 cents/lb (CP*6/5 = 48)

Basically, you need to mix 35 cents/lb (Salt 1) with 50 cents/lb (Salt 2) to get a mixture costing 40 cents/lb (Salt Avg)

weight of Salt1/weight of Salt2 = (Salt2 - SaltAvg)/(SaltAvg - Salt1) = (50 - 40)/(40 - 35) = 2/1
We know that weight of salt 1 is 40 lbs. Weight of salt 2 must be 20 lbs.

Answer (A)

Check these posts for details of this method:
http://www.veritasprep.com/blog/2011/03 ... -averages/
http://www.veritasprep.com/blog/2011/04 ... -mixtures/
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Re: How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 08 Aug 2012, 04:26
First From: x*1.2=48
Thus for 20% profit the cost should be 40c/lb.

Now fastest way is to use alligation.
salt A Salt B
35 50
40
10 5

expalanation: 40-35=5 and 50-40=10
10:5 is the ratio in which A and B are mixed
ie 2:1

if A is 40lbs then B is 20lbs
Alligation is the fastest way for these kind of questions
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Re: How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 08 Aug 2012, 14:14
I agree to find the price where 20% profit = 48 cents a bag, which is 1.2x=.48, so the cost you are looking for is .4 or 40 cents.

Now just set average cost of materials = .4

Where x = pounds at price of 50 cents...

(.5x + .35(40))/(x+40) = .4

gets you down to .1x=2

x = 20 , choice A
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Re: How many pounds of salt at 50 cents/lb must be mixed [#permalink] New post 08 Aug 2012, 22:41
1.2y=48
y=40

50x+35*40=40(x+40)
x=20
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Re: How many pounds of salt at 50 cents/lb must be mixed   [#permalink] 08 Aug 2012, 22:41
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