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How many prime numbers between 1 and 100 are factors of

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Senior Manager
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New post 24 Aug 2006, 23:23
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many prime numbers between 1 and 100 are factors of 7,150 ?

I got 3 -->2,5, 143 why is the OA 4? double count of 5?
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New post 25 Aug 2006, 00:03
Thanks VP another careless mistake
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New post 26 Aug 2006, 09:16
7150 = 2x5x5x11x13

prime factors are 2,5,11,13 = 4
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New post 26 Aug 2006, 09:37
question should probably read "distinct prime number factors" for clarity. No double counting allowed 8-)

2*5^2*11*13

Answer is 4
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New post 26 Aug 2006, 15:36
BG wrote:
143=11x13


A simple test for 11 divisibility is add alternate #s and subtarct from the other set.

For eg

143

Add 1 and 3 at odd positions

and subtract the sum of the numbers at even positions ie., 4 in this case

(1+3) - 4 = 0

||ly test for any # 1232
1+3 = 4
2+2=4

4-4 =0 so divisible by 11
  [#permalink] 26 Aug 2006, 15:36
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How many prime numbers between 1 and 100 are factors of

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