x2suresh,

You're counting single and double-digit numbers as well with the 999 - (999 / 3) method

You want to find the largest 2-digit number that is divisible by 3, which is 99 and then the largest 3-digit number divisible by 3 which is 999.

999 - 99 = 900

900 / 3 = 300

Now how many 3 digit numbers are there anyway?

there should be 900. [999 - 99 = 900]

So 900 - 300 = the answer of 600.

x2suresh wrote:

x97agarwal wrote:

How many three-digit integers are not divisible by 3 ?

599

600

601

602

603

three digit integers divisible by 3 = 999/3 = 333

three digit integers not divisible by 3 = 999-333=666

I don't see answer..

Am I missing something

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J Allen Morris

**I'm pretty sure I'm right, but then again, I'm just a guy with his head up his a$$.

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