How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4 : Quant Question Archive [LOCKED]
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# How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4

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How many way 5 rings can go on 4 fingers? (A) 3x4 (B) 5C4 [#permalink]

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27 Dec 2004, 13:11
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

How many way 5 rings can go on 4 fingers?
(A) 3x4
(B) 5C4
(C) 5P4
(D) 5^4
(E) 4^5
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27 Dec 2004, 21:14
5 choices for the 1st finger, 4 for the 2nd, etc so my answer is C, 5P4.
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27 Dec 2004, 23:09
Agree with C. This is a permutation problem whereby there is no replacement of selected items. Once the first ring goes onto the first finger, there will be 4 rings left to choose from for the 2nd finger and so on. B would have been the answer to: In how many ways can one select four rings out of 5.
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28 Dec 2004, 05:49
The answer was (E): 4^5 which I don't get either. I came out the same result as you guys. Can someone explain?
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28 Dec 2004, 07:00
E is clearly wrong. It is assuming that the same ring can be used again for another finger once picked.
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02 Jan 2005, 21:04
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S
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02 Jan 2005, 21:07
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

Wow, that never crossed my mind! You are so right
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Paul

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02 Jan 2005, 21:22
saurya_s wrote:
It will be 4^5 if you assume one can put all rings on a finger ie more than one ring per finger is possible.
S

I guess I built in an assumption that wasn't in the problem. I thought that you couldn't have more than 1 ring on each finger. I understand the answer now.
02 Jan 2005, 21:22
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