Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized for You

we will pick new questions that match your level based on your Timer History

Track Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

It appears that you are browsing the GMAT Club forum unregistered!

Signing up is free, quick, and confidential.
Join other 500,000 members and get the full benefits of GMAT Club

Registration gives you:

Tests

Take 11 tests and quizzes from GMAT Club and leading GMAT prep companies such as Manhattan GMAT,
Knewton, and others. All are free for GMAT Club members.

Applicant Stats

View detailed applicant stats such as GPA, GMAT score, work experience, location, application
status, and more

Books/Downloads

Download thousands of study notes,
question collections, GMAT Club’s
Grammar and Math books.
All are free!

Thank you for using the timer!
We noticed you are actually not timing your practice. Click the START button first next time you use the timer.
There are many benefits to timing your practice, including:

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

12 Aug 2012, 23:48

3

This post received KUDOS

1

This post was BOOKMARKED

Galiya wrote:

How many ways are there of placing 6 marbles in 4 bowls, if any number of them can be placed in each bowl?

A. 6C4 B. 6P4 C. 4^6 D. 6^4 E. 6!

whats wrong with D?

source:gogmat

Forget about permutations and combinations, I mean what the process is called. Think how would you do it: Take the first marble and think what you can do with it. Where can you place it? - you have 4 options, as there are 4 bowls Take the second marble - 4 options again, you don't care about the previous one already placed Third marble - still 4 bowls available, still have the freedom to chose any one ... You are choosing a bowl for each marble. This will give you \(4^6\) possibilities.

D would be the correct answer for example if we have 6 bowls and 4 marbles. first marble to place - 6 choices second marble - again 6 choices ... This will give you \(6^4\) possibilities. _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

15 Aug 2012, 23:59

2

This post received KUDOS

Josefeg wrote:

Bunuel wrote:

Galiya wrote:

How many ways are there of placing 6 marbles in 4 bowls, if any number of them can be placed in each bowl?

A. 6C4 B. 6P4 C. 4^6 D. 6^4 E. 6!

whats wrong with D?

source:gogmat

Each marble has 4 options, so there are total of 4*4*4*4*4*4=4^6 ways.

Answer: C.

Bunuel:

In another excercise (I cannot attach the link because this is my second post and the system is not allowing me) you explained this:

The total number of ways of dividing n identical items among r persons, each one of whom, can receive 0,1,2 or more items is (n+r -1)C(r-1).

Following this statement, taking in mind Persons = Bowls, I have to think that the answer to this question is 9C3 = 9! / 3!6! = 84. But it is incorrect according to your post. Could you please explain a little further?

Thanks a lot, José

It wasn't stated explicitly, but we all assumed in our solutions, that all the marbles are distinct/different (think of different colors or numbered marbles). Then the above solutions are correct. The number of possibilities to place 6 distinct/different marbles in 4 bowls is \(4^6.\)

If the marbles are all identical, the bowls are distinct, then what is different between the distributions is the particular number of marbles in each bowl. In this case, the above formula you mentioned should be used. For example, 6 identical marbles can be placed in 4 bowls in (6 + 4 - 1)C(4 - 1) = 9C3 = 84 ways. In the original question, since none of the listed answers is 84, the hidden assumption was that the marbles are non-identical, which I think it should have been stated explicitly.

For \(n\) identical marbles and \(r\) bowls, a way to justify the formula is as follows: think of the of the marbles placed in slots instead of bowls. The slots are aligned, created such that there are \(r-1\) dividing internal walls, something like this: [o|ooo|...| |o| ], where [ and ] represent the two outer walls of the slots. In the first slot there is one ball, in the second three balls,..., there is an empty slot, just one ball, and the last one is also an empty slot. In each slot, we can place any number of marbles between 0 and r. Imagine that we have \(n+r-1\) places, because we have \(n\) marbles and \(r-1\) dividing walls, and we just have to decide in this string of length \(n+r-1\) where to place the walls (or equivalently, where to place the marbles). This can be done in (n + r - 1)C(r - 1) different ways, or equivalently, (n + r - 1)Cn. _________________

PhD in Applied Mathematics Love GMAT Quant questions and running.

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

12 Aug 2012, 16:56

1

This post received KUDOS

Galiya wrote:

why cant i use permutation?

have 4 slots: - - - - and for each slot there are 6 marbles, hence 6^4

Because there are more than "4 slots". By doing the slot method and saying that there are 4 bowls, hence 4 slots, you are saying that each bowl can only hold 1 marble. Problem is that a bowl can hold 1,2,3,4,5, or all 6 marbles. So instead of calculating how many options there are for the bowls to hold, it's simpler to find how many options each marble has.

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

13 Aug 2012, 00:09

1

This post received KUDOS

EvaJager wrote:

Galiya wrote:

How many ways are there of placing 6 marbles in 4 bowls, if any number of them can be placed in each bowl?

A. 6C4 B. 6P4 C. 4^6 D. 6^4 E. 6!

whats wrong with D?

source:gogmat

Forget about permutations and combinations, I mean what the process is called. Think how would you do it: Take the first marble and think what you can do with it. Where can you place it? - you have 4 options, as there are 4 bowls Take the second marble - 4 options again, you don't care about the previous one already placed Third marble - still 4 bowls available, still have the freedom to chose any one ... You are choosing a bowl for each marble. This will give you \(4^6\) possibilities.

D would be the correct answer for example if we have 6 bowls and 4 marbles. first marble to place - 6 choices second marble - again 6 choices ... This will give you \(6^4\) possibilities.

Lets have a different problem Their are 4 alphabets Set A ( A,B,C,D) and 6 Numbers SET N ( 1,2,3,4,5,6) Q.1 : In how many ways can 4 alphabets be assigned a number from 1 to 6 without any restrictions Q.2 : In how many ways can 6 numbers be assigned an alphabet from A to D without any restriction These two should clear your doubt and to make these easy start adding restrictions to them like use all elements of set A, Set N, map uniquely , no element used twice, etc And these two questions can be formed in any way to show all concepts of Permutations, combinations, distributions, De-distribution and even to bose einstien distribution.

and can you think of a condition that will make this mapping a function ?

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

12 Aug 2012, 19:17

Galiya wrote:

why cant i use permutation?

have 4 slots: - - - - and for each slot there are 6 marbles, hence 6^4

You are distributing marbles to slots .. not slots to marbles !

The reason you cant use permutations is that you are not permuting ! It is a pure distribution problem. The distribution problems have a different strategy than permutation and combinations.

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

15 Aug 2012, 14:23

Bunuel wrote:

Galiya wrote:

How many ways are there of placing 6 marbles in 4 bowls, if any number of them can be placed in each bowl?

A. 6C4 B. 6P4 C. 4^6 D. 6^4 E. 6!

whats wrong with D?

source:gogmat

Each marble has 4 options, so there are total of 4*4*4*4*4*4=4^6 ways.

Answer: C.

Bunuel:

In another excercise (I cannot attach the link because this is my second post and the system is not allowing me) you explained this:

The total number of ways of dividing n identical items among r persons, each one of whom, can receive 0,1,2 or more items is (n+r -1)C(r-1).

Following this statement, taking in mind Persons = Bowls, I have to think that the answer to this question is 9C3 = 9! / 3!6! = 84. But it is incorrect according to your post. Could you please explain a little further?

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

16 Aug 2012, 09:56

EvaJager wrote:

It wasn't stated explicitly, but we all assumed in our solutions, that all the marbles are distinct/different (think of different colors or numbered marbles). Then the above solutions are correct. The number of possibilities to place 6 distinct/different marbles in 4 bowls is \(4^6.\)

Eva, thanks a lot for your explanation. I also think that it should have been stated.

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

28 Jun 2014, 07:38

Hello from the GMAT Club BumpBot!

Thanks to another GMAT Club member, I have just discovered this valuable topic, yet it had no discussion for over a year. I am now bumping it up - doing my job. I think you may find it valuable (esp those replies with Kudos).

Want to see all other topics I dig out? Follow me (click follow button on profile). You will receive a summary of all topics I bump in your profile area as well as via email. _________________

Re: How many ways are there of placing 6 marbles in 4 bowls [#permalink]

Show Tags

13 Jul 2014, 08:20

Quote:

Lets have a different problem Their are 4 alphabets Set A ( A,B,C,D) and 6 Numbers SET N ( 1,2,3,4,5,6) Q.1 : In how many ways can 4 alphabets be assigned a number from 1 to 6 without any restrictions Q.2 : In how many ways can 6 numbers be assigned an alphabet from A to D without any restriction These two should clear your doubt and to make these easy start adding restrictions to them like use all elements of set A, Set N, map uniquely , no element used twice, etc And these two questions can be formed in any way to show all concepts of Permutations, combinations, distributions, De-distribution and even to bose einstien distribution.

and can you think of a condition that will make this mapping a function ?

Wow! Nice explanation EvaJagger, Bunuel and mandyrhtdm! A lot of doubts cleared from one single thread! Kudos to all

@mandrhtdm just to confirm..the answers are Q1 \(4^6\) Q2 \(6^4\) right?

gmatclubot

Re: How many ways are there of placing 6 marbles in 4 bowls
[#permalink]
13 Jul 2014, 08:20

So, my final tally is in. I applied to three b schools in total this season: INSEAD – admitted MIT Sloan – admitted Wharton – waitlisted and dinged No...

HBS alum talks about effective altruism and founding and ultimately closing MBAs Across America at TED: Casey Gerald speaks at TED2016 – Dream, February 15-19, 2016, Vancouver Convention Center...

By Libby Koerbel Engaging a room of more than 100 people for two straight hours is no easy task, but the Women’s Business Association (WBA), Professor Victoria Medvec...