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Order does matter so this is a permutation problem. Since we have no repeating elements, then use the standard formula for selecting K elements from a pool of N elements:

Yes, since you are only picking numbers, picking ABC is supposedly to be the same with picking CBA, so it is a combination problem. We have C(5,3)=5!/2!3!. For easier calculation I always do this: C(5,3)=C(5,2)=5*4/2!=10

If the question asks how many different three letter words can you form, then order matters since ABC is a different word from CBA. In that case the answer would be P(5,3)=5*4*3=60. _________________

Keep on asking, and it will be given you;
keep on seeking, and you will find;
keep on knocking, and it will be opened to you.

It does not matter in what order letters are chosen, so it's a combination problem. if each letter can be chosen only once, then C(5,3)=5!/3!(5-3)!=10 _________________

I´ve done an interview at Accepted.com quite a while ago and if any of you are interested, here is the link . I´m through my preparation of my second...

It’s here. Internship season. The key is on searching and applying for the jobs that you feel confident working on, not doing something out of pressure. Rotman has...