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How many weeks was the Carnival open last year? (1) The [#permalink ]
02 Jun 2009, 22:15

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How many weeks was the Carnival open last year?

(1) The ratio between the number of weeks it was open and closed last year is

1:3 .

(2) The multiple of the number of weeks the Carnival was open and the number of weeks the Carnival was closed is

507 .

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the answer is C, 1, insuffucient X/y = 1/3 =>3X = Y but no idea of the x,y 2, insufficient.. x*y*k = 507 = 3*13*13 when k = 1, x=3 and y = 39 or x = 39 or y = 3 combining 1 and 2 , 3x^2 K = 507 x^2 K = 169.. when k = 1, X = 13, y = 39/... Whats the OA ?

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Hades wrote:

How many weeks was the Carnival open last year? (1) The ratio between the number of weeks it was open and closed last year is 1:3 . (2) The multiple of the number of weeks the Carnival was open and the number of weeks the Carnival was closed is 507 .

C

x=open

y=closed

x/y=1/3

xy=507

3x^2=507

x=13

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Good attempts

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Hades wrote:

Good attempts

must be E..there are only 52 weeks in a year

52 factors to 13*2*2...no combo will give you 1/3 so cant be A

507 factors to 13*13*3 ...no sum adds to 52, cant be B

did you make this question up?

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How many weeks was the Carnival open last year?

(1) The ratio between the number of weeks it was open and closed last year is .

(2) The multiple of the number of weeks the Carnival was open and the number of weeks the Carnival was closed is 507.

Answer D

1 - one year -52 weeks

the ratio ==> x:3x

4x=52

x=52/4 =13

2.507=3x13x13

we can derive from B also. Number of weeks when open + number of weeks when closed should be 52 and change the multiples.

As 507 is a multiple 0f 13 and 52 is a multiple of 13, we can solve from stat 2.

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X - # of weeks open

Y - # of weeks closed

X + Y = 52 (inferred)

Question:

(X?) (1)

X/Y = 1/3 2 linear equations, 2 variables

\longrightarrow SUFFICIENT .

(2)

XY = 507 Rearrange inferred equation to

Y = 52-X and substitute into above

X(52-X) = 507 52X - X^{2} = 507 X^{2} - 52X + 507 = 0 X^{2} - 13X - 39X + 507 = 0 X(X - 13) - 39(X - 13) = 0 (X - 13)(X - 39) = 0 \longrightarrow X=13 or

X=39 \longrightarrow INSUFFICIENT .

Final Answer,

A .

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Thanks amolsk.

And yes bigtreezl, I actually did. My questions are sneaky MF'ers.

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i am sure i am gonna leave out such ones.. Hades, What is the source of such brilliant questions ..?

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Neochronic wrote:

i am sure i am gonna leave out such ones.. Hades, What is the source of such brilliant questions ..?

My brain my friend,

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