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How much water (in grams) should be added to the

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CEO
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How much water (in grams) should be added to the [#permalink] New post 03 Jan 2008, 08:38
How much water (in grams) should be added to the 35%-solution of 50g solution of acid to obtain the 10% solution?

Please show your work.
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Re: easy mixture [#permalink] New post 03 Jan 2008, 08:56
bmwhype2 wrote:
How much water (in grams) should be added to the 35%-solution of 50g solution of acid to obtain the 10% solution?

Please show your work.


the percentage of acid in the resulting solution will be:

[0.35·50/(50+x)]=0.1 therefore x=125 g
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Re: easy mixture [#permalink] New post 03 Jan 2008, 09:08
Easiest way:

35% of 50 grams = 17.5 grams
if we want to have a 10% solution then 17.5 will be 1/10 of the total
Multiply by 10 to see that final solution must be 175 grams
175-50 = 125 grams of water
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Re: easy mixture [#permalink] New post 05 Jan 2008, 07:08
125.
find how much solute we have, and that must be 10% of resulting solution.
so we have, 35% 0f 50= 17.5 solute
so 175 total soln required,
so add 125 to 50 and make it 175
Re: easy mixture   [#permalink] 05 Jan 2008, 07:08
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