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How to solve these kind of problems?

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How to solve these kind of problems? [#permalink] New post 24 Sep 2007, 14:42
Hi,
I am hard time to solve problems like the followings. Thus, if you know any general formula that can be use to solve these kinds of problems, please let me know. In other words, what is the best way to approach to these kind of the problems?


Problem #88(from OG11)
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

The correct answer should be 68.

GMATPrep question:
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

The correct answer should be 25.

Question #1 is discussed here: a-necklace-is-made-by-stringing-n-individual-beads-together-37754.html
Question #2 is discussed here: according-to-the-directions-on-a-can-of-frozen-orange-juice-101577.html
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Re: How to solve these kind of problems? [#permalink] New post 24 Sep 2007, 14:51
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3



According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans
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Re: How to solve these kind of problems? [#permalink] New post 24 Sep 2007, 18:30
GMAT_700 wrote:
Hi,
I am hard time to solve problems like the followings. Thus, if you know any general formula that can be use to solve these kinds of problems, please let me know. In other words, what is the best way to approach to these kind of the problems?


Problem #88(from OG11)
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

The correct answer should be 68.

GMATPrep question:
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

The correct answer should be 25.


1st one. Well the pattern has to be RGWBYRGW this equals 5 +3. So we have to find a number that allows this pattern. 5(x)+3. 5*13+3=68.

Answer D.

2nd one:

I have seen this so many times on this forum.

Ratio is O/W=1/3 so x+3x= total

4x= total. 6*200=1200 (total ounces) x=300

Now since we want to know 12 ounce orange juice cans. Just divide 12 by 300

300/12=25. Also I think u can do it this way. x+4x=200 x=50. Since we are using 6 ounce cans we divide this by 2. again 25.

Answer A
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 [#permalink] New post 24 Sep 2007, 18:56
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

The sequence goes r-g-w-b-y. So after every 5 beads, a new set begins. And the third bead after a new set is the white bead. So just count of the multiples of 5 and add 3 to see if your answer is in... for instance...

16. Nearest multiple of 5 is 15, 1 bead after 15 is red. --> out
32. Nearest multiple of 5 is 30, 2 beads after 30 is green. --> out
41. Nearest multiple of 5 is 40. 1 bead after 40 is red. --> out
54. Nearest multiple of 5 is 50. 4 beads after 50 is blue. --> out
68. Nearest multiple of 5 is 65. 3 beads after 65 is white --> Ans.
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 [#permalink] New post 24 Sep 2007, 19:02
According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100


Each mixture has 4 cans of solutions (1 can concentrate + 3 cans water)

There are total of 1200 ounces of servings in all.
This requires 1200/12 = 100 parts of mixture. (Assume the parts are mixed with 12 ounce cans)
# of cans of concentrate needed is 100/4 = 25.
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Re: How to solve these kind of problems? [#permalink] New post 23 Dec 2013, 08:57
bkk145 wrote:
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3



According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans



Is this correct or Just Lucky?: The ratio of concentrate to water is 1:3 and They need 100 12oz servings to make 200 6oz servings.

So I did: 1x + 3x = 100

4x=100
x= 25
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Re: How to solve these kind of problems? [#permalink] New post 24 Dec 2013, 00:53
Expert's post
lsantos08 wrote:
bkk145 wrote:
A necklace is made by stringing N individual beads together in the repeating pattern red bead, green bead, white bead, blue bead, and yellow bead. If the necklace design begins with a red bead and ends with a white bead, then N could equal:
a) 16
b) 32
c) 41
d) 54
e) 68

R,G,W,B,Y
Five beads in pattern and ends with white. Therefore, the number of beads will be 5*integer + 3
The only number that fits is 68 = 5*13+3



According to the directions on a can of frozen orange juice concentrate, 1 can of concentrate is to be mixed with 3 cans of water to make orange juice. How many 12-ounce cans of the concentrate are required to prepare 200 6-ounce servings of orange juice?

a)25
b)34
c)50
d)67
e)100

One can of 12 ounces concentrated can produce 4*12 = 48 ounces of OJ.
You want 200 ounces with 6 serving, which is 6*200 = 1200 ounces
Therefore, you need: 1200/48 = 25 cans



Is this correct or Just Lucky?: The ratio of concentrate to water is 1:3 and They need 100 12oz servings to make 200 6oz servings.

So I did: 1x + 3x = 100

4x=100
x= 25


Yes, that's correct.
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Re: How to solve these kind of problems? [#permalink] New post 24 Dec 2013, 00:55
Expert's post
1
This post was
BOOKMARKED
Question #1 is discussed here: a-necklace-is-made-by-stringing-n-individual-beads-together-37754.html
Question #2 is discussed here: according-to-the-directions-on-a-can-of-frozen-orange-juice-101577.html
_________________

NEW TO MATH FORUM? PLEASE READ THIS: ALL YOU NEED FOR QUANT!!!

PLEASE READ AND FOLLOW: 11 Rules for Posting!!!

RESOURCES: [GMAT MATH BOOK]; 1. Triangles; 2. Polygons; 3. Coordinate Geometry; 4. Factorials; 5. Circles; 6. Number Theory; 7. Remainders; 8. Overlapping Sets; 9. PDF of Math Book; 10. Remainders; 11. GMAT Prep Software Analysis NEW!!!; 12. SEVEN SAMURAI OF 2012 (BEST DISCUSSIONS) NEW!!!; 12. Tricky questions from previous years. NEW!!!;

COLLECTION OF QUESTIONS:
PS: 1. Tough and Tricky questions; 2. Hard questions; 3. Hard questions part 2; 4. Standard deviation; 5. Tough Problem Solving Questions With Solutions; 6. Probability and Combinations Questions With Solutions; 7 Tough and tricky exponents and roots questions; 8 12 Easy Pieces (or not?); 9 Bakers' Dozen; 10 Algebra set. ,11 Mixed Questions, 12 Fresh Meat

DS: 1. DS tough questions; 2. DS tough questions part 2; 3. DS tough questions part 3; 4. DS Standard deviation; 5. Inequalities; 6. 700+ GMAT Data Sufficiency Questions With Explanations; 7 Tough and tricky exponents and roots questions; 8 The Discreet Charm of the DS ; 9 Devil's Dozen!!!; 10 Number Properties set., 11 New DS set.


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Re: How to solve these kind of problems?   [#permalink] 24 Dec 2013, 00:55
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