Can anyone tell me how to solve this problem?
Jack and joe are 150 miles apart in a straight line. Jack leaves from A at a speed of 30 miles per hour. Joe leaves from B at a speed of 50 miles per hour. When they meet each other, how far is joe from the starting point of Jack i.e, A.?
Using d = st,
for Jack, d = 30t
for Joe , (150-d) = 50t
d/(150-d) = 3/5 => 5d = 450-3d => d = 450/8 => 56.25 miles.
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