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# http://gmatclub.com/tests/m06#expl2

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http://gmatclub.com/tests/m06#expl2 [#permalink]  12 Mar 2008, 09:58

Pls explain. Thanks!!!
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Re: http://gmatclub.com/tests/m06#expl2 [#permalink]  12 Mar 2008, 17:29
Please post the question, so that people like me who do not have access to questions can still analyse the same and try to answer them.
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http://gmatclub.com/tests/m06#expl2 [#permalink]  13 Mar 2008, 09:18
Sorry...here's the question:
Attachments

M6 #2.doc [41 KiB]

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Re: http://gmatclub.com/tests/m06#expl2 [#permalink]  13 Mar 2008, 16:01
The expression in your document can be re-written as Sqrt((x+3)^2) + Sqrt((y-1)^2)
Which employs => (x+3) + (y-1) we need to find value of this expression
When x = 3/4 and y = 2/5

3/4 + 3 + 2/5 - 1 = (15 + 60 + 8 - 20)/20 = 63/20

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Re: http://gmatclub.com/tests/m06#expl2 [#permalink]  13 Mar 2008, 21:41
(x+3) + (y-1)

but its not addition as per the question - its subtraction.
Re: http://gmatclub.com/tests/m06#expl2   [#permalink] 13 Mar 2008, 21:41
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