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29 Oct 2006, 12:20
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SVP
Joined: 01 May 2006
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29 Oct 2006, 12:39
(E) for me

(x-y)/(x+y) > 1 ?
<=> (x-y)/(x+y) - 1 > 0
<=> [(x-y) - (x+y)]/(x+y) > 0
<=> -2*y/(x+y) > 0

That implies
o -2*y > 0 thus y < 0 and x+y>0 thus x > -y > 0 (case 1)
or
o -2*y < 0 thus y > 0 and x+y<0 thus x < -y < 0 (case 2)

Stat 1
x > 0 is not enough. We have to know something about y such as y < 0.

INSUFF

Stat 2
y < 0 is not enough. We have to know something about x such as x > -y.

INSUFF

(1) and (2) together

As y < 0 and x > 0, We are more in the case 1. But we have to know if x > -y to conclude.

INSUFF
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29 Oct 2006, 13:06
simplified as

X-Y > X+Y

star 1
X>0 , Y can be -ive or postive
Y -IVE
X= 3, Y = -5

3-(-5) > 3+ (-5)
=> 8>-2

but when Y Positive
3-5<3+5

Not suffi

stat 2
Y<0, X can be -ive or positive
X -ive
X = -3 Y= -5
-3-(-5)> -3+(-5)
2>-8 correct

x +ive
10 - (-3) > 10 + (-3)

SVP
Joined: 01 May 2006
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29 Oct 2006, 13:21
ashuspark wrote:
simplified as

X-Y > X+Y

star 1
X>0 , Y can be -ive or postive
Y -IVE
X= 3, Y = -5

3-(-5) > 3+ (-5)
=> 8>-2

but when Y Positive
3-5<3+5

Not suffi

stat 2
Y<0, X can be -ive or positive
X -ive
X = -3 Y= -5
-3-(-5)> -3+(-5)
2>-8 correct

x +ive
10 - (-3) > 10 + (-3)

Sorry ashuspark ... but I think we cannot simplified as u did. We do not know the sign of X+Y : if X+Y < 0, then we have to flip the sign.
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29 Oct 2006, 13:54

shaaaaa
doing sad mistakes wat i am going to do test in a week
29 Oct 2006, 13:54
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