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# http://www.manhattangmat.com Did anyone try this problem ??

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http://www.manhattangmat.com Did anyone try this problem ?? [#permalink]

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03 Feb 2004, 08:25
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

http://www.manhattangmat.com

Did anyone try this problem ?? I am getting E as the answer.
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03 Feb 2004, 09:33
Got C also. This problem is clearly about the Pythagorean theorem
First, just find the ground distance between the current position and the re-routed position:
distance = (15^2 + 8^2 )^1/2 = 289^1/2

Actual distance between current position and re-routed position:
distance = (289^1/2 + 6^2)^1/2 = 325^1/2 = 5 * 13^1/2

Actual distance between current position and original position:
distance = (8^2 + 6^2)^1/2 = 100^1/2 = 10

Speed differential in order to arrive on time:
Distance/Time = Speed
NB Time is 1/20 because 3minutes = 1/20 hour
= (5 * 13^1/2 - 10) / (1/20)
= 20 * (5 * 13^1/2 - 10)
= 100 * SQR13 - 200
_________________

Best Regards,

Paul

Last edited by Paul on 03 Feb 2004, 09:53, edited 1 time in total.
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Re: 02/02/2004 - Manhattan GMAT problem [#permalink]

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03 Feb 2004, 09:48
Geethu wrote:
www.manhattangmat.com

Did anyone try this problem ?? I am getting E as the answer.

I think you did the problem correctly upto certain point but than what the question is asking is "By how many miles per hour pilot has to increase the speed? "

What you found is I think "What should be the speed of plan to reach the new destination on time?"
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03 Feb 2004, 11:00
Got C.
Attachments

Slide1.JPG [ 20.8 KiB | Viewed 529 times ]

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03 Feb 2004, 13:10
Hi Geethu,

You calculated the speed necessary to land at 8 PM. But the question is asking the increase in the speed.

Anand.
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04 Feb 2004, 08:40
Thank you guys. I see the difference now.
04 Feb 2004, 08:40
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# http://www.manhattangmat.com Did anyone try this problem ??

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