Hypotenuse : Quant Question Archive [LOCKED]
Check GMAT Club Decision Tracker for the Latest School Decision Releases http://gmatclub.com/AppTrack

 It is currently 16 Jan 2017, 17:37

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# Hypotenuse

Author Message
Manager
Joined: 01 May 2008
Posts: 114
Location: São Paulo
Followers: 1

Kudos [?]: 6 [0], given: 0

### Show Tags

04 May 2008, 15:42
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

Can anyone help me with this question?

Tks
Attachments

Doc2.doc [47.5 KiB]

Director
Joined: 20 Feb 2008
Posts: 797
Location: Texas
Schools: Kellogg Class of 2011
Followers: 6

Kudos [?]: 147 [0], given: 9

### Show Tags

04 May 2008, 16:39
For starters you know two sides are equal since a right isoceles triangle has two equal sides. The perimeter formula for a triangle is A + B + C = P or for this problem: 16 + 16√2 = P Also, you know the sides are in the ratio 1:1:√2. So there are two possible answers:

1. The two short sides of the triangle add up to 16. Thus the hypotenuse is 16√2. We can check by using the pythagorean theorem.

8^2 + 8^2 = (16√2)^2

64 + 64 = (256 * 2), obviously this does not add up

2. The second option is that 16 is the hypotenuse and (16√2) is the length of each short side. Therefore each side would be 8√2.

(8√2)^2 + (8√2)^2 = 16^2

128 + 128 = 256, which is the correct answer.

Therefore the correct answer is B, 16.
Re: Hypotenuse   [#permalink] 04 May 2008, 16:39
Display posts from previous: Sort by