I would go with E on this one. I solved half this problem with formula and the other half with logically plugging in numbers.

Let A = weight of box A

Let B = weight of box B

Let C = weight of box C

Let T = total weight available in the truck

Let X = total weight of all other boxes in the truck

In this problem, we have to assume that the weight ALREADY in the truck is B + X

From stem 1: A + B > T - (B + X) --> A + B > T - B - X

From stem 2: (T - X) - B > C --> T - B - X > C

Combining both formulas, we get A + B > T - B - X > C

I) says that T - B - X < C which is total opposite of the combined formula. This is false

II) At this point, I plugged in numbers. Say for instance that box B is 25 pounds and box C is 30 pounds, then in order to be able to load box C after removing box B, the available weight left on the truck must be at least 5 pounds; the difference between box B and C. This is true.

III) This says A > abs val (B - C). The combined formula from above is A + B > T - B - X > C which simplifies to A + B > C

A > C - B. This is true

Therefore, II and III are true and E is the answer

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Best Regards,

Paul