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I am not sure about this. Can someone assist? If one [#permalink] New post 14 Dec 2003, 08:08
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I am not sure about this. Can someone assist?

If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?


a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8
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Re: PS - Probability [#permalink] New post 14 Dec 2003, 09:17
tzec76 wrote:
I am not sure about this. Can someone assist?

If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?


a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8



first find how many numbers are multiples of both 2 and 8

simply put, every number divisible by 8 will be divisible by 2

first # divisible by 8 .. 8

last # divisible by 8 ...1000

total #'s ......(1000-8)/8 +1 = 124 +1= 125


total numbers = 1000

prob = 125 /1000 = 1/8
Re: PS - Probability   [#permalink] 14 Dec 2003, 09:17
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