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Manager
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14 Dec 2003, 07:08
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If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?

a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8
CEO
Joined: 15 Aug 2003
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14 Dec 2003, 08:17
tzec76 wrote:

If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?

a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8

first find how many numbers are multiples of both 2 and 8

simply put, every number divisible by 8 will be divisible by 2

first # divisible by 8 .. 8

last # divisible by 8 ...1000

total #'s ......(1000-8)/8 +1 = 124 +1= 125

total numbers = 1000

prob = 125 /1000 = 1/8
Re: PS - Probability   [#permalink] 14 Dec 2003, 08:17
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