Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 28 Oct 2016, 17:25

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# I am not sure about this. Can someone assist? If one

 post reply Question banks Downloads My Bookmarks Reviews Important topics
Author Message
Manager
Joined: 29 Apr 2003
Posts: 93
Location: Singapore
Followers: 1

Kudos [?]: 0 [0], given: 0

I am not sure about this. Can someone assist? If one [#permalink]

### Show Tags

14 Dec 2003, 08:08
00:00

Difficulty:

(N/A)

Question Stats:

0% (00:00) correct 0% (00:00) wrong based on 0 sessions

### HideShow timer Statistics

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I am not sure about this. Can someone assist?

If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?

a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8
CEO
Joined: 15 Aug 2003
Posts: 3460
Followers: 68

Kudos [?]: 848 [0], given: 781

Re: PS - Probability [#permalink]

### Show Tags

14 Dec 2003, 09:17
tzec76 wrote:
I am not sure about this. Can someone assist?

If one number is chosen at random from the first 1,000
positive integers, what is the probability that the number
chosen is a multiple of both 2 and 8?

a. 1/125
b. 1/8
c. 1/2
d. 9/16
e. 5/8

first find how many numbers are multiples of both 2 and 8

simply put, every number divisible by 8 will be divisible by 2

first # divisible by 8 .. 8

last # divisible by 8 ...1000

total #'s ......(1000-8)/8 +1 = 124 +1= 125

total numbers = 1000

prob = 125 /1000 = 1/8
Re: PS - Probability   [#permalink] 14 Dec 2003, 09:17
Display posts from previous: Sort by

# I am not sure about this. Can someone assist? If one

 post reply Question banks Downloads My Bookmarks Reviews Important topics

 Powered by phpBB © phpBB Group and phpBB SEO Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.