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I am so sorry! I do not know why I cannot post the right

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Manager
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I am so sorry! I do not know why I cannot post the right [#permalink] New post 26 Apr 2007, 20:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I am so sorry! I do not know why I cannot post the right question. I have tried and tried but to no avail.

Anyway I have written out the stmts, hopefully that will work! :roll:

If x and y are integers and

y=lx+3l+l4-xl does y equal 7?

Stmt 1 says that x is less that 4

Stmt 2 says x is greater than -3


[/b]

Last edited by ninomoi on 28 Apr 2007, 12:30, edited 2 times in total.
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 [#permalink] New post 26 Apr 2007, 21:21
This seems like a DS. Do you want to correct the question?
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 [#permalink] New post 28 Apr 2007, 12:33
I have re wriiten the question folks! Pls help!!!! :(
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 [#permalink] New post 28 Apr 2007, 12:53
(C) for me :)

lx+3l+l4-xl = 7 ?

From1
X < 4, implies that :
lx+3l+l4-xl
=|x+3| + (4-x)

After that, to go more ahead, we have to case to remove the second absolute:
o If x > -3
lx+3l+l4-xl
=|x+3| + (4-x)
= x+3 + 4 -x
= 7

o If x < -3
lx+3l+l4-xl
=|x+3| + (4-x)
= -(x+3) + 4 -x
= -2*x + 7

INSUFF.

From2
X > -3, implies that :
lx+3l+l4-xl
=(x+3) + |4-x|

After that, to go more ahead, we have to case to remove the second absolute:
o If x < 4
lx+3l+l4-xl
=(x+3) + |4-x|
=(x+3) + (4-x)
= 7

o If x > 4
lx+3l+l4-xl
=(x+3) + |4-x|
=(x+3) + -(4-x)
= 2*x - 1

INSUFF.

Both (1) & (2)
We have -3 < x < 4. Thus,

lx+3l+l4-xl
=(x+3) + (4-x)
= 7

SUFF.
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 [#permalink] New post 28 Apr 2007, 12:57
Given: x and y are integers and y=lx+3l+l4-xl

Asked: does y equal 7?

(1) x is less than 4
Solution domain of y is found by plugging 4 for x, which leads to y=7
now, if x is less than 4 then try x = 3 which gives y = 7
but if x is - 10, then y = 21

So, statement 1 is insufficient


(2) x is greater than -3
try x = -3 .. gives y = 7
try x = -2 .. gives y = 7
but if x = 10 .. then y = 19

statement 2 is insufficient

(1) and (2) together
I hope by now you see the pattern and how these two statement build a solution domain for values of x that result in y = 7
As long as x is less than 4 and larger than -3, the value of y will always be 7, of course given that x and y are integers.

So, statements 1 and 2 together are sufficient to answer the question

My Answer: C
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 [#permalink] New post 28 Apr 2007, 22:00
Thanks guys! The answer is C.
  [#permalink] 28 Apr 2007, 22:00
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I am so sorry! I do not know why I cannot post the right

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