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# I came across this problem and I hope that some of you can

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Senior Manager
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I came across this problem and I hope that some of you can [#permalink]

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16 Nov 2005, 11:41
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I came across this problem and I hope that some of you can explain to me how you can get the correct answer:

If 8*(2x+3)=2*(3X=6), then x =

A. -3
B. -1
C. 0
D. 1
E. 3

The OA on this problem is B, but I dont exactly understand how to solve it. Please help!
VP
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Re: OG 10th Edition #90 [#permalink]

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16 Nov 2005, 11:49
Puilunchristin wrote:
I came across this problem and I hope that some of you can explain to me how you can get the correct answer:

If 8*(2x+3)=2*(3X=6), then x =

A. -3
B. -1
C. 0
D. 1
E. 3

The OA on this problem is B, but I dont exactly understand how to solve it. Please help!

Is there a typo in the question?
Senior Manager
Joined: 16 Jul 2005
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16 Nov 2005, 12:08
what do you mean a typo?

Maybe it's the way I typed in on this forum

But it is 8 with the exponent of 2x+3 = 2 with the exponent of 3x+6
Director
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16 Nov 2005, 12:10
2 ^ 3*(2x +3) = 2 ^ (3x +6)

or,
6x +9 = 3x + 6

or x =-1..

btw.. exponent is denoted by ^
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Director
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16 Nov 2005, 12:21
yup

equate the power of same base

3(2X+3)=3X+6

X=-1
16 Nov 2005, 12:21
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