I disagree with the OA on this one. What is the median : DS Archive
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I disagree with the OA on this one. What is the median

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Senior Manager
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I disagree with the OA on this one. What is the median [#permalink]

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03 Jul 2005, 10:26
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I disagree with the OA on this one.

What is the median number of employees assigned per project for the projects at Company Z?

(1) 25 percent of the projects at Company Z have 4 or more employees assigned to each project.

(2) 35 percent of the projects at Company Z have 2 or fewer employees assigned to each project.
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03 Jul 2005, 10:42
I will go with C
Suppose there are 100 projects, we are interested in the number of people working on project 50 & 51
Statement 1:
76,......100 has 4 or more people working
so, 50, 51 will be 1, 2 or 3
Statement 2:
1.........35 has 2 or less than 2 people working
so, 50, 51 can be 3, 4 or more.

Both statements together
1........35 is 2 or less
76......100 is 4 or more & 35......75 is 3
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03 Jul 2005, 10:44

What if each of the project that has 4 or more employees, has 1000 employees in it?
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03 Jul 2005, 10:47
So you are saying projects
76 thru 100 has 1000 employees right. This will not change the median because the median is the middle number when they are arranged in an ascending order.
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03 Jul 2005, 10:51

If there are 100 projects 25 have 2 employees, 40 have 3 employees and 35 have 1000 employees, then what is the median?
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03 Jul 2005, 10:54
C.

at minimum 1 project means 5% of projects

so there are at least 5 projects that are 4+
7 projects that have 2- people
and 8 projects with 3 people => median is defined it is 3
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03 Jul 2005, 10:58
AJB77 wrote:

If there are 100 projects 25 have 2 employees, 40 have 3 employees and 35 have 1000 employees, then what is the median?

It will still be 3

Projects 1 thru' 25 will have 2 employees
Projects 26 thru' 65 will have 3 employees (our median falls in this range)
Projects 66 thru' 100 will have 1000 employees

Since projects 50, 51 has 3 employees this will be our median.

If you write this down, it will be clearer.

2,2,2,2,2,2,2,2,2.......upto 25 then
3,3,3,3,3,3,3,3,3.......upto 65 then
1000, 1000, 1000,.......upto 100 - we really do not need to worry about this as long as we know that they are greater than 3
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03 Jul 2005, 11:03
Thanks, got it now. Brain lock
03 Jul 2005, 11:03
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