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I do not agree with the OA here...

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Senior Manager
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I do not agree with the OA here... [#permalink]

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New post 10 Aug 2006, 15:03
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I do not agree with the OA here....
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 [#permalink]

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New post 10 Aug 2006, 15:10
Allow me to try on this one

It is two evenly spaced sets (ie: mean = median)

From st. one we can tell that set s = (-2 , -1 , 0 , 1 , 2)

But it say nothing about set T THUS INSUFF

Statment two that the sum of set T = sum of thus clearly insuff

Taking them together

S = T = ZER0 THUS SUFF BECAUSE WITH an odd numbered set ( 7 elements) to give a sum of zero and given that the numbers are consecutive then the median is zero.


I hope i am right ... what is OA
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 [#permalink]

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New post 10 Aug 2006, 16:26
gmatornot wrote:
yezz wrote:
Allow me to try on this one

It is two evenly spaced sets (ie: mean = median)

From st. one we can tell that set s = (-2 , -1 , 0 , 1 , 2)

But it say nothing about set T THUS INSUFF

Statment two that the sum of set T = sum of thus clearly insuff

Why is this INSUFF ?

won't the only possibility be zero ? other 2 sets having 5 consecutive and 7 consecutive integers should have differenct sums right ?


Taking them together

S = T = ZER0 THUS SUFF BECAUSE WITH an odd numbered set ( 7 elements) to give a sum of zero and given that the numbers are consecutive then the median is zero.


I hope i am right ... what is OA


Let terms in S be : x-2, x-1, x, x+1, x+2 , then sum = 5x
terms in T be : y-3, y-2, y-1, y, y+1, y+2, y+3

Sum of S = Sum of T
5x = 7y

one solution as you described is x = y = 0
there can be other solutions, e.g. x = 7, y = 5
then S becomes {5, 6, 7, 8, 9}, sum = 35
T becomes {2, 3, 4, 5, 6, 7, 8}. sum = 35

there may be other solutions, when x = -7, y = -5 etc.
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Re: GMATPrep - DS -Median [#permalink]

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New post 13 Aug 2006, 16:35
gmatornot wrote:
I do not agree with the OA here....


This is a tough one
(1) s{ -2 -1 0 1 2}
T{-3 -2 -1 0 1 2 3}
Yes med of S = Med of T

s{ -2 -1 0 1 2}
T{ 2,3,4,5,6,7,8}
Med of S Not equal to Med of T

BCE

(2) s{ -2 -1 0 1 2}
T{-3 -2 -1 0 1 2 3}
med are equal
Or
S{5 6 7 8 9}
T{ 2 3 4 5 6 7 8 }
Med not equal
CE

(1)&(2)
s{ -2 -1 0 1 2}
T{-3 -2 -1 0 1 2 3}

Hence C

Heman

gmatornot I see that u are online :p can you post teh OA to this one.
Re: GMATPrep - DS -Median   [#permalink] 13 Aug 2006, 16:35
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I do not agree with the OA here...

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