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I found it quite interesting and they said this is one of [#permalink]
05 Jun 2006, 01:07

I found it quite interesting and they said this is one of the most difficult questions in Gmat. Be careful
Sequence S consists of 24 non-zero intergers. From the third one, every term of S is the product of the previous 2 terms. How many terms in S are negative?
(1) The third term in S is Positive
(2) The fourth term in S is negative
Good luck!!!

B it is.
(1) The third term in S is Positive
it gives two possible sequesnces: -
(+ve, +ve ,+ve .............+ve) or (-ve, -ve, +ve, -ve, -ve, +ve........)
so we can't count the number of -ve integers.

(2) The fourth term in S is negative
It gives the following sequences: -
(-ve, +ve, -ve, -ve, +ve, -ve, -ve, +ve, -ve, ......so on)
or
(-ve, -ve, +ve, -ve, -ve, +ve, -ve, -ve, +ve, ......so on)

If you see, in both the above series a pattern is repeated after 3 numbers, i.e. 2 negative and 1 positive numbers. So there are 16 -ve numbers in the series. _________________

If A equals success, then the formula is: A = X + Y + Z, X is work. Y is play. Z is keep your mouth shut.
Albert Einstein

"(2) The fourth term in S is negative
It gives the following sequences: -
(-ve, +ve, -ve, -ve, +ve, -ve, -ve, +ve, -ve, ......so on)
or
(-ve, -ve, +ve, -ve, -ve, +ve, -ve, -ve, +ve, ......so on) "
I think this is an excellent answer. Because of the repetition of every 3 terms with 2negative and 1 positive so we can get the answer from (2). And the OA is obviously B.