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I found this problem on the internet while trying to find [#permalink]
26 Oct 2007, 10:02

This topic is locked. If you want to discuss this question please re-post it in the respective forum.

I found this problem on the internet while trying to find some practice material:

Tom has 30 apples, 15 of them are bad.Steve has 30 oranges and 6 of them are bad. Both Tom and Steve have to put two apples and two oranges in a basket at random. What is the probability that the basket would have exactly two bad apples and two bad oranges?

I tried to solve it but looks like something is missing..........can someone help.

Why do we add the probability of these two events? These are two mutually exclusive events, and we are looking for the probability of 1 event AND the other event.

Why do we add the probability of these two events? These are two mutually exclusive events, and we are looking for the probability of 1 event AND the other event.

AND ---> multiply

Last edited by KillerSquirrel on 26 Oct 2007, 14:21, edited 1 time in total.

Well if you throw a dice twice, what is the probability that you throw six both times?
P = (1/6)*(1/6) = 1/36

What if the question had asked what is the probability of selecting 2 bad apples or 2 bad oranges? The result would have two scenarios, which would provide for p = p(1) + p(2). Thoughts?

Well if you throw a dice twice, what is the probability that you throw six both times? P = (1/6)*(1/6) = 1/36

What if the question had asked what is the probability of selecting 2 bad apples or 2 bad oranges? The result would have two scenarios, which would provide for p = p(1) + p(2). Thoughts?

Well if you throw a dice twice, what is the probability that you throw six both times?

P = (1/6)*(1/6) = 1/36

What if the question had asked what is the probability of selecting 2 bad apples or 2 bad oranges? The result would have two scenarios, which would provide for p = p(1) + p(2). Thoughts?

probability of selecting 2 bad apples or 2 bad oranges ?

I found this problem on the internet while trying to find some practice material:

Tom has 30 apples, 15 of them are bad.Steve has 30 oranges and 6 of them are bad. Both Tom and Steve have to put two apples and two oranges in a basket at random. What is the probability that the basket would have exactly two bad apples and two bad oranges?

I tried to solve it but looks like something is missing..........can someone help.

agree with calculations 7/29 x 1/29 = 7/29^2, but the result seems too low...

I found this problem on the internet while trying to find some practice material:

Tom has 30 apples, 15 of them are bad.Steve has 30 oranges and 6 of them are bad. Both Tom and Steve have to put two apples and two oranges in a basket at random. What is the probability that the basket would have exactly two bad apples and two bad oranges?

I tried to solve it but looks like something is missing..........can someone help.

agree with calculations 7/29 x 1/29 = 7/29^2, but the result seems too low...

Well... it's 1 chance on 120 to have this specific set ... I think it's fine, the number of bad orange is low too

If the number of bad oranges were also equal to the good one, a set like this would have 1 chance on 17 to be...