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I guess you already know this. How beautyful even simple

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Director
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I guess you already know this. How beautyful even simple [#permalink]

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New post 15 Jan 2006, 12:47
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I guess you already know this. How beautyful even simple math can be!

3^6x = 8100

Then what is 3^(x-1)^3 ?
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New post 15 Jan 2006, 13:41
3^6x = 8100

=3^(x-1)^3
=(3^x/3)^3
=3^3x/3^3
=[(3^6x)^1/2]/3^3
=8100^1/2/3^3
=90/27
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New post 15 Jan 2006, 18:28
10/3

3^(x-1)^3 = 3^3x-3 = 3^3x/3^3 .

given the 3^6x = 8100. => 3^3x = sqrt(8100) = 90

the 90/3*3*3 = 10/3
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New post 15 Jan 2006, 23:42
allabout wrote:
I guess you already know this. How beautyful even simple math can be!

3^6x = 8100

Then what is 3^(x-1)^3 ?


3^(x-1)^3 = (3^3x)/27 - equn 1
Given 3^(6x) = 8100
Suaring equn 1 gives.
(3^6x)/27^2
= 8100/27*27
= 10/3
Re: PS - Just for fun   [#permalink] 15 Jan 2006, 23:42
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