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# I have asked many math experts and nobody can figure this

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Eternal Intern
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I have asked many math experts and nobody can figure this [#permalink]  08 Jun 2003, 11:41
I have asked many math experts and nobody can figure this out.

If * denotes a math operation, does x * y = y *x for all x and y

( 2) Statement Two is not sufficient but why?

(2 ) For all y, 0 * y= 2y^2.
Founder
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Re: Is this legitimate [#permalink]  08 Jun 2003, 11:45
Expert's post
Curly05 wrote:
I have asked many math experts and nobody can figure this out.

If * denotes a math operation, does x * y = y *x for all x and y

( 2) Statement Two is not sufficient but why?

(2 ) For all y, 0 * y= 2y^2.

Check this problem again. Statement 1 is missing; what do you do with them?
Eternal Intern
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Complete Chaos [#permalink]  08 Jun 2003, 12:40
If * denotes a mathematical operation, does X * Y= Y *X for all x and y?

( 1) For all x and y, x * y= 2( x^2 + y^2) - Statement One is Enough.

( 2 ) For all y, O * y= 2y^2. - It's not sufficient but why?

ETS's crappy explanation.

There are many possible definitions of x * y for which 0 * y= 2y^2- for example x *y= x + 2y^2 or x *y= ( x + 1)( 2y^2). If we consider x *y= x + 2y^2 and then y * X = y + 2x^2. But it is not true that x + 2y^2= y + 2x^2.

Now, it would help if they were more concrete.

But, I think I saw this somewhere before on ETS's symbolism.

When they turn around X* Y to Y * X, they mean for Y *X and that Y takes that part of X and X takes the part of Y, etc.

I'll let Bogdan explain.
Victor
Complete Chaos   [#permalink] 08 Jun 2003, 12:40
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