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# I'm having problems w/these

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I'm having problems w/these [#permalink]  22 Nov 2009, 16:45
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They're not too hard, but I can't seem to solve correctly.

A) Solve for P2

E = A1P1 + A2P2 + A3P3

I get P2 = -E + A1P1 + A3P3/-A2

B) Solve the equation

abs. value ($$\frac{x-4}{3}$$) + 2 = 4

I start w/two equations:

$$\frac{x-4}{3}$$ + 2 = 4

$$\frac{-x+4}{-3}$$ + 2 = 4

I get 10 = x in both equations.
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Re: I'm having problems w/these [#permalink]  22 Nov 2009, 18:23
ggarr wrote:
They're not too hard, but I can't seem to solve correctly.

A) Solve for P2

E = A1P1 + A2P2 + A3P3

I get P2 = -E + A1P1 + A3P3/-A2

I Did not get this one.

ggarr wrote:
B) Solve the equation

abs. value ($$\frac{x-4}{3}$$) + 2 = 4

I start w/two equations:

$$\frac{x-4}{3}$$ + 2 = 4

$$\frac{-x+4}{-3}$$ + 2 = 4

I get 10 = x in both equations.

The second one: (4-x)/3 + 2 = 4

Multiply only numerator not denominator by -ve.

$$\frac{x-4}{3}$$ and $$\frac{-x+4}{-3}$$ are same.
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Re: I'm having problems w/these [#permalink]  23 Nov 2009, 00:13
In A, you are moving variables incorrectly.

Quote:
A) Solve for P2

E = A1P1 + A2P2 + A3P3

I get P2 = -E + A1P1 + A3P3/-A2

A2P2 = E - A1P1 - A3P3

Then to
$$P2 = \frac{E - A1P1 - A3P3}{A2}$$

It's easier to keep the variable that you are isolating as positive rather than moving it where it would be negative.

With this one: $$|\frac{x-4}{3}| + 2 = 4$$ you do need to separate it into 2 equations, but I think this is where you made the mistake.

We have to simplify it first

$$|\frac{x-4}{3}| + 2 = 4$$

-2 from both sides
$$|\frac{x-4}{3}| = 2$$

now separate into 2 equations

$$\frac{x-4}{3} = 2$$ and $$\frac{x-4}{3} = -2$$

First you get
$$x-4 = 6$$; therefore x = 10

and $$x-4=-6$$ +4 to both sides means x = -2

So the two answers for x are 10 and -2

These questions are not very detailed and are not like the real GMAT questions. Is each question posted in the same way you found it? If there is more context, please post that. Also, please state the source of the question when posting it.
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Re: I'm having problems w/these   [#permalink] 23 Nov 2009, 00:13
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