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i made a guess on this one. it was intuitive to me how to do

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Current Student
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Joined: 28 Dec 2004
Posts: 3385
Location: New York City
Schools: Wharton'11 HBS'12
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i made a guess on this one. it was intuitive to me how to do [#permalink]

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New post 31 May 2008, 13:30
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

i made a guess on this one. it was intuitive to me how to do it..
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Manager
Manager
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Joined: 28 May 2008
Posts: 94
Followers: 2

Kudos [?]: 8 [0], given: 0

Re: G-Prep Geometry [#permalink]

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New post 31 May 2008, 13:43
Hi
I could try to explain this one
Let the angle PTR=a------ (!)
so,PRT=(90-a)right?-------(1)
Now,in triangle RQS
since QR=RS
This means angle RQS=angleRSQ right?-------(2)
sum of angles of a triangle=180
Using (1)and (2) RSQ=RQS=(180-(90-a))/2 =(90+a)/2 ------(3)
Similarly for triangle UST
UTS=PTR=a (from(!))
The other two angles of this triange would be (180-a)/2-----(4)

Using 3 and 4 and property of a straight line(sum=180)
(90+a)/2 + x + (180-a)/2 = 180
x=45 degrees

Hope that helps.
I wanted todraw a figure and show you. But I couldnt
Apologies !

Cheers !!
Manager
Manager
avatar
Joined: 28 May 2008
Posts: 94
Followers: 2

Kudos [?]: 8 [0], given: 0

Re: G-Prep Geometry [#permalink]

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New post 31 May 2008, 13:44
zeenie wrote:
Hi
I could try to explain this one
Let the angle PTR=a------ (!)
so,PRT=(90-a)right?-------(1)
Now,in triangle RQS
since QR=RS
This means angle RQS=angleRSQ right?-------(2)
sum of angles of a triangle=180
Using (1)and (2) RSQ=RQS=(180-(90-a))/2 =(90+a)/2 ------(3)
Similarly for triangle UST
UTS=PTR=a (from(!))
The other two angles of this triange would be (180-a)/2-----(4)

Using 3 and 4 and property of a straight line(sum=180)
(90+a)/2 + x + (180-a)/2 = 180
x=45 degrees

Hope that helps.
I wanted todraw a figure and show you. But I couldnt
Apologies !

Cheers !!


I forgot to mention.The above solution is reached after using both A and B
Hence (C)is the answer :)
Current Student
avatar
Joined: 28 Dec 2004
Posts: 3385
Location: New York City
Schools: Wharton'11 HBS'12
Followers: 15

Kudos [?]: 258 [0], given: 2

Re: G-Prep Geometry [#permalink]

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New post 01 Jun 2008, 07:30
zeenie wrote:
zeenie wrote:
Hi
I could try to explain this one
Let the angle PTR=a------ (!)
so,PRT=(90-a)right?-------(1)
Now,in triangle RQS
since QR=RS
This means angle RQS=angleRSQ right?-------(2)
sum of angles of a triangle=180
Using (1)and (2) RSQ=RQS=(180-(90-a))/2 =(90+a)/2 ------(3)
Similarly for triangle UST
UTS=PTR=a (from(!))
The other two angles of this triange would be (180-a)/2-----(4)

Using 3 and 4 and property of a straight line(sum=180)
(90+a)/2 + x + (180-a)/2 = 180
x=45 degrees

Hope that helps.
I wanted todraw a figure and show you. But I couldnt
Apologies !

Cheers !!


I forgot to mention.The above solution is reached after using both A and B
Hence (C)is the answer :)



Yeah OA is C..

i didnt workout the whole thing but realized that with the 2 statements i could figure out x..
Re: G-Prep Geometry   [#permalink] 01 Jun 2008, 07:30
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i made a guess on this one. it was intuitive to me how to do

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