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I Never knew much about cars-Ps

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I Never knew much about cars-Ps [#permalink] New post 20 Aug 2003, 04:13
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The radiator of an automobile is filled to capacity with 8 liters of a solution that is 20% liquid x. The automobile engine overheats, and 6 liters of water evaporate, leaving 2 liters of concentrated liquid x solution If the radiator is refilled with 6 liters of a solution that is 20% liquid x, what will be the concentration of the resulting solution?

A. 20%
B. 25%
C. 30%
D. 35%
E. 40%
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 [#permalink] New post 20 Aug 2003, 07:25
I am not too sure about this but I think the answer choices are wrong.
Out of 8 liters..20% is X which makes 1.6 litres of X.

now 6 liters of 'Water evapourates' hence 1.6 is still retained in the engine. An additional 6 literes of mix soln is filled in, out of which 20% is soln x(1.2)..Yes if you see it this way then the answer is 40% 1.6+1.2=2.8..2.8/6*100=40%..

But the confusing part is that in the problem it mentions 2 litres of X after the water evapourates...in that case it would be 2+1.2(the addnal X from the new 6litres) which makes it 3.2 which is well over 50% and that choice doesnt seem to be in choices given. Please explain which is the right answer..

Thanks :?
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Answer [#permalink] New post 20 Aug 2003, 07:26
D.

Original solution has 1.6L of X and 6.4 L of water.
Take away 6L of water and we have 1.6L of X and .4L of water.
Now add 1.2L of x and 4.8L of water.

we have 2.8L of X out of a total volume of 8.

2.8/8 = .35
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 [#permalink] New post 20 Aug 2003, 07:45
I got it.. The answer should be 2.8/8 which makes it 35%...Oh lord..cant believe I fell for the trap.

Thanks
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 [#permalink] New post 20 Aug 2003, 10:49
8L contains 1.6 of X and 6.4 of Water. 6L of waer gone.
So 2L contains 1.6 of X and 0.4 of Water
6L of 20% - 1.2 of X and 4.8 of Water

New solution is again 8L and now we have 1.6L + 1.2L of X = 2.8L

% of X = (2.8 / 8) x 100 = 35%

So D
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 [#permalink] New post 20 Aug 2003, 11:34
satgates wrote:
I got it.. The answer should be 2.8/8 which makes it 35%...Oh lord..cant believe I fell for the trap.

Thanks


That's great that you made that mistake here, rather than on the test. When I first started studying for the GMAT I had a problem that was osmething like "If a company of 3000 employees was 1/3 women, and 300 women quit, what is the new percentage of women". Well, I figured out everything right, but what i went to do the final percentage, I did not take away the women that quit form the total employees. You made a similar error. So now, you will always remember this problem and not make the mistake again. Therefore, you are successful.
  [#permalink] 20 Aug 2003, 11:34
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