Find all School-related info fast with the new School-Specific MBA Forum

 It is currently 02 Jul 2015, 22:20

### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

# Events & Promotions

###### Events & Promotions in June
Open Detailed Calendar

# I understand this problem, but the solution is based on the

Author Message
TAGS:
Intern
Joined: 15 Jun 2008
Posts: 8
Followers: 0

Kudos [?]: 0 [0], given: 0

I understand this problem, but the solution is based on the [#permalink]  13 Jul 2008, 13:15
1
This post was
BOOKMARKED
I understand this problem, but the solution is based on the distance of the drive wheel=distance of the mixing wheel. No problem there. Thats 2 wheels, what happened to the 3rd wheel?
Attachments

m05q23.jpg [ 148.71 KiB | Viewed 706 times ]

Manager
Joined: 15 Dec 2008
Posts: 52
Schools: HBS(08) - Ding. HBS, Stanford, Kellogg, Tuck, Stern, all dings. Yale - Withdrew App. Emory Executive -- Accepted, Matriculated, Withdrewed (yes, I spelled it wrong on purpose). ROSS -- GO BLUE 2011.
Followers: 1

Kudos [?]: 48 [0], given: 1

Re: m05 question 23 - what happened to the 3rd wheel [#permalink]  17 Mar 2009, 07:14
dariusbanasik wrote:
I understand this problem, but the solution is based on the distance of the drive wheel=distance of the mixing wheel. No problem there. Thats 2 wheels, what happened to the 3rd wheel?

The third wheel "remains in the middle."

The distance the motor and mixing wheels travel is equal -- you stated you understand that.

The distance the middle wheel travels is also the same.

If the middle wheel had a radius of 6,000,000 miles, it would turn the same "distance" as a middle wheen with radius of 1 nanometer.

The number of rotations would be vastly different, but in the end it would still turn the mixing wheel the same "distance" that the motor wheel turn it (the middle wheel).

Therefore since they all turn the same distance, you can essentially ignore the middle (third) wheel.
Re: m05 question 23 - what happened to the 3rd wheel   [#permalink] 17 Mar 2009, 07:14
Similar topics Replies Last post
Similar
Topics:
5 One-fourth of a solution that was 10% by weight was replaced 9 04 Oct 2008, 02:53
Solution Problem 3 25 Jan 2009, 11:19
SOLUTIONS, acid and water, help to understand the OE please 6 01 Sep 2007, 05:01
Exponents Problem solution 2 11 Mar 2007, 15:21
The purpose of this problem is to check your understanding 6 09 Nov 2005, 04:54
Display posts from previous: Sort by