I've listed some questions that took me WAY too long to

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I've listed some questions that took me WAY too long to [#permalink]

28 Jun 2006, 10:15

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I've listed some questions that took me WAY too long to answer (much more than 2mins.), and I got 3/4 wrong. Anyhow, can someone suggest shortcuts to answering the below? anything other than having to plug in several numbers, etc. They're all out of the OG 11th, btw.
Thanks.

All DS

119. Is 2x-3y< x^2?
1. 2x-3y=-2
2. x>2 and y>0

139. If x does not equal -y, is x-y/x+y >1?
1. x>0
2. y<0

140. In the rectangular coordinate system, are points (r,s) and (u,v) equidistant from the origin?
1. r+s=1
2. u=1-r and v=1-s

For this next one-- can someone pls tell me why B and not D is the answer.

146. Is n an integer?
1. n^2 is an integer
2. sqr. root of n is an integer

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28 Jun 2006, 10:40

119)
#1. 2x-3y=-2, and value of x is not known. But since 2x-3y<0 and x^2>0, this statement is sufficient (assuming, of course, that x is not an imaginary number, in which case x^2 < 0)

#2. x>2 and y>0. Also sufficient. Try plugging in numbers.

Answer should be D.

139)
#1. x>0. Insuffiencient
#2. y<0. Sufficient.

Answer should be B.

140)
#1. r+s=1; does not say anything about u and v. Hence insufficient.
#2. u^2 + v^2 = (1-r)^2 + (1-s)^2 = 2-2(r+s)=(r^2 + s^2). Insufficient.

Combining the two, we get u^2+v^2=r^2+s^2. Answer C.

146)
True. D should be the answer. Both seem sufficient. What is OE?

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Re: 4 DS questions from OG 11-- [#permalink]

28 Jun 2006, 11:37

Longhorn wrote:

(D) Both are sufficient.

Longhorn wrote:

139. If x does not equal -y, is x-y/x+y >1?
1. x>0
2. y<0

(E)
I. Insufficient -- Try {5,2} and {5, -4}
II. Insufficient -- Try {10, -9} and {10, -1}

Combining, still insufficient, use examples from II.

Longhorn wrote:

140. In the rectangular coordinate system, are points (r,s) and (u,v) equidistant from the origin?
1. r+s=1
2. u=1-r and v=1-s

Longhorn wrote:

For this next one-- can someone pls tell me why B and not D is the answer.

146. Is n an integer?
1. n^2 is an integer
2. sqr. root of n is an integer

(B)
I. Insufficient. n^2 = 8, gives n = sqrt (8) which is not an integer.
II. sufficient.

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28 Jun 2006, 11:59

Yeah. Messed up 139 and 146. sgrover is right.

Last edited by paddyboy on 28 Jun 2006, 12:14, edited 1 time in total.

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28 Jun 2006, 12:06

paddyboy wrote:

Yeah. Messed up 139 and 146. v1rok is right.

I assume you mean sgrover .. :wink:

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28 Jun 2006, 12:13

Mom! Look! A Boo Boo!!

Apparently, I messed up the post as well

Huge big Apologies!!!!!!!! Post edited...

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29 Jun 2006, 03:31

A)D
1) Suff. square is positive hence greater than negative number
2) Put values and u will see 2x-3y<x^2

B)E

C) C

1) r+s =2 not suff. Don't know anything about u,v
2) u=1-r v=1-s
Equidistant from origin then
r^2 +s^2 = U^2 +v^2
r^2 +s^2 = r^2+s^2+2-2(r+s)
2-2(r+s) = 0
Not suff dont know what r and s are.

Both
r=s = 2 hence 2 becomes 0 proved

D) B
1) n^2 = 10 Hence n not an integer
2) SqrN = 10 , Hence N = 100 Integer. Suff

[#permalink] 29 Jun 2006, 03:31

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I've listed some questions that took me WAY too long to

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