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If 0 < x < 1, is it possible to write x as a terminating dec

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If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 24 Jun 2013, 01:20
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If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 24 Jun 2013, 01:32
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If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer --> 24x=m, where m an integer --> x=\frac{m}{24}=\frac{m}{2^3*3}, If m is a multiple of 3, then the answer is YES, else the answer is NO. Not sufficient.

(2) 28x is an integer --> 28x=n, where n an integer --> x=\frac{n}{28}=\frac{n}{2^2*7}, If n is a multiple of 7, then the answer is YES, else the answer is NO. Not sufficient.

(1)+(2) x=\frac{m}{2^3*3}=\frac{n}{2^2*7} --> \frac{m}{n}=\frac{2*3}{7} --> m IS a multiple of 3 (as well as n IS multiple of 7). Sufficient.

Answer: C.

Theory:
Reduced fraction \frac{a}{b} (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only b (denominator) is of the form 2^n5^m, where m and n are non-negative integers. For example: \frac{7}{250} is a terminating decimal 0.028, as 250 (denominator) equals to 2*5^2. Fraction \frac{3}{30} is also a terminating decimal, as \frac{3}{30}=\frac{1}{10} and denominator 10=2*5.

Note that if denominator already has only 2-s and/or 5-s then it doesn't matter whether the fraction is reduced or not.

For example \frac{x}{2^n5^m}, (where x, n and m are integers) will always be the terminating decimal.

We need reducing in case when we have the prime in denominator other then 2 or 5 to see whether it could be reduced. For example fraction \frac{6}{15} has 3 as prime in denominator and we need to know if it can be reduced.

Questions testing this concept:
does-the-decimal-equivalent-of-p-q-where-p-and-q-are-89566.html
any-decimal-that-has-only-a-finite-number-of-nonzero-digits-101964.html
if-a-b-c-d-and-e-are-integers-and-p-2-a3-b-and-q-2-c3-d5-e-is-p-q-a-terminating-decimal-125789.html
700-question-94641.html
is-r-s2-is-a-terminating-decimal-91360.html
pl-explain-89566.html
which-of-the-following-fractions-88937.html

Hope it helps.
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Re: If 0 < x < 1, is it possible to write x as a terminating [#permalink] New post 27 Jun 2013, 21:37
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If 0 < x < 1, is it possible to write x as a terminating decimal?
(1) 24x is an integer.
(2) 28x is an integer.


Reduced fraction \frac{a}{b} (meaning that fraction is already reduced to its lowest term) can be expressed as terminating decimal if and only b (denominator) is of the form 2^n5^m, where m and n are non-negative integers

Statement 1- If 24x is an integer than x can take the following values
1/2, 1/3, 1/4, 1/6, 1/8, 1/12, 1/24
Some values of x can be reduced to a terminating decimal (1/2, 1/4, 1/8), while few can not be (1/3,1/6,1/12, 1/24)
Insufficient

Statement 2- If 28x is an integer than x can take the following values
1/2, 1/4, 1/7, 1/14, 1/28
Some values of x can be reduced to a terminating decimal (1/2, 1/4), while few can not be (1/7, 1/14, 1/28)
Insufficient

Statement 1& 2- If both 24x & 28x are integers than x can take the following values
1/2, 1/4
Both of these values of x can be reduced to a terminating decimal
Sufficient

Ans C.

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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 28 Jul 2013, 10:18
Can someone explain me what is the meaning of terminating decimal.
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 28 Jul 2013, 10:25
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trafficspinners wrote:
Can someone explain me what is the meaning of terminating decimal.


A decimal number that has digits that do not go on forever.

Examples:

0.25 (it has two decimal digits)
0.123456789 (it has nine decimal digits)

In contrast a Recurring Decimal has digits that go on forever

Example of a Recurring Decimal: 1/3 = 0.333... (the 3 repeats forever)
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 20 Aug 2013, 03:16
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Rock750 wrote:
If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.


I have a bit of difficulty in understanding the intended meaning of "is it possible" part of the question.

The answer can be yes and ofcourse no, but just that there is a possibility that the answer could be yes confuses me a bit. Had the question been framed like this " is x a terminating decimal?", then it would have been clearer. The use of the term "possible" makes it just a bit ambiguous.

Put up for guidance please.
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 20 Aug 2013, 04:57
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agourav wrote:
Rock750 wrote:
If 0 < x < 1, is it possible to write x as a terminating decimal?

(1) 24x is an integer.

(2) 28x is an integer.


I have a bit of difficulty in understanding the intended meaning of "is it possible" part of the question.

The answer can be yes and ofcourse no, but just that there is a possibility that the answer could be yes confuses me a bit. Had the question been framed like this " is x a terminating decimal?", then it would have been clearer. The use of the term "possible" makes it just a bit ambiguous.

Put up for guidance please.


The question basically asks: if x is written as a decimal will it be a terminating decimal?

Hope it's clear.
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 06 Sep 2013, 10:58
since the question asks "is it possible", wouldn't the answer be D since .5 is a terminating decimal and 24*.5=12, and 28*.5=24?
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 07 Sep 2013, 04:30
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thebloke wrote:
since the question asks "is it possible", wouldn't the answer be D since .5 is a terminating decimal and 24*.5=12, and 28*.5=24?


You misinterpret the question. The question asks: if x is written as a decimal will it be a terminating decimal? Thus the correct answer is C, not D.
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Re: If 0 < x < 1, is it possible to write x as a terminating dec [#permalink] New post 05 Jan 2014, 08:48
we know that x is a proper positive fraction. we need to check whether x has powers of 5 or 2 in the denominator or not.

1. 24(x)=INT ---> x=Int/24 if our integer is 3 then x is can be written as a terminating decimal otherwise x will be a non-terminating decimal

2. 28(x)=INT ----> same story here if our int is 7 then x can be written as a terminating decimal, otherwise x will be a non-terminating decimal

1+2 Int/3(2^3)=Int/7(2^2) -----> 7(4)Int=8(3)Int the expression has to be equal on both sides thus on the right hand side we need a 7 and on the right hand side we need a 3 and a two. We now know that our integer a terminating decimal because we can get rid of both 7 and 3 in the denominator.

C.

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Re: If 0 < x < 1, is it possible to write x as a terminating dec   [#permalink] 05 Jan 2014, 08:48
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