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Re: If 0 < x < 1, which of the following inequalities must be [#permalink]
08 Oct 2008, 07:36

My two cents:

I beeter if you divided by x^2: x^2+x^3<x+1 -> always II better if you divided by x^2: x^2-x^3<1-x^2 always III dividing by x^2: x^2-x^3<1-x^2 if x=0.1 thus 0.01-0.001<1-0.01 always if x=0.9 thus 0.81-0.729<1-0.9 // 0.081<1 always

Re: If 0 < x < 1, which of the following inequalities must be [#permalink]
08 Oct 2008, 08:01

I also believe the answer is E since even the third equation, x^4 - x^5 < x^2 - x^3 = x^4 + x^3 < x^2 + x^5 =x^2 + x < 1+x^3 which is true since the value on the right hand side will be greater than 1.

Given the recent news this is way overdue, but see below my first interview report for INSEAD. I met with a senior politician alum who, understandably, had a busy schedule. The...

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